Question

(5x+7)(8x+7) = 0Find the two possible values.​

Answer 1

Hi!

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$\rightsquigarrow\circ\boldsymbol{Explanation}\circ\leftharpoonup$

Set each factor equal to 0.

$\twoheadrightarrow\sf 5x+7=0$

$\twoheadrightarrow\sf 8x+7=0$

$\bullet$ Solve each equation

$\twoheadrightarrow\sf 5x+7=0$

$\bullet$ Subtract 7 from both sides

$\twoheadrightarrow\sf 5x=-7$

$\bullet$ Divide both sides by 5

$\underline{\twoheadrightarrow\sf x=-\cfrac{7}{5}}$

$\bullet$ Now let's solve the second equation

$\twoheadrightarrow\sf 8x+7=0$

$\bullet$ Subtract 7 from both sides

$\twoheadrightarrow\sf 8x=-7$

$\bullet$ Divide both sides by 8

$\underline{\twoheadrightarrow\sf x=-\cfrac{7}{8}}$

$\bullet$ Great job, we found the two possible values

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Hope that this helped! Best wishes.

$\textsl{Reach far. Aim high. Dream big.}\\\boldsymbol{-Greetings!-}$

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Answer 2

$(5x + 7)(8x + 7) \\ \\ 5x + 7 = 0 \\ \\ 5x = - 7 \\ \\ x = \frac{ - 7}{5} \\ \\ 8x + 7 = 0 \\ \\ 8x = - 7 \\ \\ x = \frac{ - 7}{8} .$

the values of x are -7/5 and -7/8 .