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iris [78.8K]
3 years ago
13

If a car decreases its speed from 80 km/h to 45 km/h in 14 seconds, what is its rate of acceleration?

Mathematics
1 answer:
VMariaS [17]3 years ago
5 0

Answer:

-2.5 km

Step-by-step explanation:

80 - 45= 35

35 / 14 sec. = 2.5

So if your decreasing it would turn that 2.5 into a negative.

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What number can be used to complete the volume statement for the cone?
Lilit [14]

Answer:

V=πr2h /3

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Solve for x I got x=28.394. is that correct?
quester [9]
Cosine 65 = 12 / x
0.4226183 = 12 / x
x = 12 / 0.4226183
<span> <span> <span> x = 28.39441</span></span></span>

So, I'd say you are correct.

6 0
3 years ago
As a marketing manager, you are tasked with selecting a website to place your advertisement. The following sampled data shows th
olasank [31]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Website 1 : 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 377999 / 36 = 10499.9722

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 1 :), s = 110.239865

Website 2 : 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 395197 / 36 = 10977.6944

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 2), s = 132.617995

2.)

Yes, the viewership between the two websites are different with the second website has a higher mean viewership with a mean of 10977.6944.

3.)

The probability of 12000 views per month on each website :

Probability = Mean viewership per month / required viewership

Website 1 :

P(12000) = 10499.9722 / 12000 = 0.8749

Website 2 :

P(12000) = 10977.6944 / 12000 = 0.9148

4.)

More consistent website :

We use the standard deviation value, the higher the standard deviation, the higher the variability :

Website 1 should be more consistent has it has a Lower standard deviation score, hence, should show lower variability than website 2.

5.)

Website suitable for advertisement should be one with higher viewership per month in other to reach a larger audience. Hence, website 2 should be recommended for advertisement.

5 0
3 years ago
Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of e
emmainna [20.7K]

This question is incomplete, the complete question is;

Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of equations in terms of x, y, z, and t.) The line passes through the point (3, 1, 2) and is parallel to the line given by x  = y = z.

Answer:

the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

Step-by-step explanation:

Given that;

line x = y = z and point ( 3, 1, 2 )

the given line can be written as;

[x-0 / 1] = [y-0 / 1] = [z-0 / 1]

if two lines are parallel directional ratios are equal.

so DIRECTIONAL RATIOS  of given line is ( 1, 1, 1 )

therefore required line is;

[x-3 / 1] = [y-1 / 1] = [z-2 / 1] = t

⇒ [x-3 / 1] = t

x = t+3

[y-1 / 1] = t

y = t+1

[z-2 / 1] = t

z = t+2

Therefore the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

8 0
3 years ago
What inergers that are greater than zero
Sav [38]
Half of all the integers are ... all of the positive "counting numbers".

The total number is infinite, so I can't list them here.  But if you start at '1 '
and count, you can never name <em>ALL</em> of them, but you can name <em>as many</em>
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4 years ago
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