9514 1404 393
Answer:
16 miles
Step-by-step explanation:
The problem can be modeled by a right triangle with one angle of 7° and the side opposite being 10,000 ft. The distance needed is the hypotenuse of the triangle, so the relevant trig relation is ...
Sin = Opposite/Hypotenuse
Hypotenuse = Opposite/Sin
air distance = (10,000 ft)/sin(7°) ≈ 82,055 ft
At 5,280 ft per mile, that is ...
(82,055 ft)/(5,280 ft/mi) ≈ 15.54 mi
The plane's air distance to the airport is about 16 miles.
Answer:
The answer for this question is A. (4,-4)
We can drop the absolute value and the signs, and the integer part if they're all the same, and then make a common denominator and check for a decreasing sequence.
10/12, 7/12, 5/12 -- Check decreasing
3 1/3, 3 2/3, 2 2/3 -- nope, increases then decreases
6 5/7, 6 3/7, 5 2/7 - Check, decreasing
11 7/10, 11 6/10, 10 3/10 -- Check, decreasing
Answer: A,C,D
Since you know that DA and DC are equal in length, you can say 2x-3=x+2, when you add 3 to both sides, it becomes 2x=x+5, subtract x from both sides, and you find that x=5
Answer : 12.4 +b
It said the longest is two times bigger then the smallest and the longest is 6.2 and thats double
