Ask question

Ask question

All categories

2 years ago

5

Multiply radicals please

1 answer:

leva [86]2 years ago

8 0

Answer:

B

Step-by-step explanation:

$~~~\left( \dfrac 1 3 \sqrt x - \dfrac 32 \sqrt y \right)^2\\\\\\=\left( \dfrac 13 \sqrt x \right)^2 + \left( \dfrac 32 \sqrt y \right)^2 - 2 \left(\dfrac 13 \sqrt x \right)\left( \dfrac 32 \sqrt y \right)\\\\\\=\dfrac 19 x+ \dfrac 94 y-\sqrt{xy}\\\\\\=\dfrac 19x - \sqrt{xy} + \dfrac 94 y$

You might be interested in

4(5x - 2) = 72<br> What do I do

Pepsi [2]

Answer:

x = 4

Step-by-step explanation:

4(5x - 2) = 72

Do the distributive property

20x - 8 = 72

Then add 8 to both sides to get 20x alone

20x - 8 = 72

+ 8 + 8

20x = 80

Then divide both sides by 20 to get x

$\frac{20x}{20} = \frac{80}{20}$

x = 4

6 0

3 years ago

Which situation can be represented by the expression -2-5−2−5minus, 2, minus, 5?

nadya68 [22]

The answer might be c

8 0

2 years ago

Jonh's collection contains 20 books including 2 historical novels if John randomly selects a book to read what is the probility

Anarel [89]

Answer:2/20 or 20%

Step-by-step explanation:

7 0

3 years ago

Please help me with ptomblem

marysya [2.9K]

Answer:

When $p^2 - 4p$ is subtracted from $p^2 + p - 6$ , the result is $5p - 6$ . To get $p - 9$ , subtract $4p + 3$ from the result.

Step-by-step explanation:

✔️Subtracting $p^2 - 4p$ from $p^2 + p - 6$ :

$(p^2 + p - 6) - (p^2 - 4p)$

$p^2 + p - 6 - p^2 + 4p$ (Distributive property)

Collect like terms

$p^2 - p^2 + p + 4p - 6$

$5p - 6$

✔️Subtracting $p - 9$ from $5p - 6$ :

$(5p - 6) - (p - 9)$

$5p - 6 - p + 9$ (distributive property)

Add like terms

$4p + 3$

3 0

2 years ago

Recall that for use of a normal distribution as an approximation to the binomial distribution, the conditions np greater than or

vagabundo [1.1K]

Answer:

The minimum sample size needed for use of the normal approximation is 50.

Step-by-step explanation:

Suitability of the normal distribution:

In a binomial distribution with parameters n and p, the normal approximation is suitable is:

np >= 5

n(1-p) >= 5

In this question, we have that:

p = 0.9

Since p > 0.5, it means that np > n(1-p). So we have that:

$n(1-p) \geq 5$

$n(1 - 0.9) \geq 5$

$0.1n \geq 5$

$n \geq \frac{5}{0.1}$

$n \geq 50$

The minimum sample size needed for use of the normal approximation is 50.

6 0

3 years ago