Answer:
Both boats will be 54 miles apart after 3 hours.
Step-by-step explanation:
Given that from a point on a river, two boats are driven in opposite directions, one at 7 miles per hour and the other at 11 miles per hour, to determine how many hours they will be 54 miles apart, the following calculation must be performed :
54 / (11 + 7) = X
54/18 = X
3 = X
Therefore, both boats will be 54 miles apart after 3 hours.
Answer:
The answer is D
Step-by-step explanation:
Coplanar means that they are on the same closed area(or plane)- P, M, C, N are all on the same Plane.
Answer: y = x^2 + 6x+ 9 = 0. (X+3)^2= 0 when x=3. This has one root.
X^2-2x -24 = 0 a= 1 b=-1 and c= -24 x = {-(-1) +/- sqrt((-1)^2 -4 x 1 x (-24)}/2
X = [1 +/- sqrt(97)]/2
Step-by-step explanation:
Answer:
The perimeter of △HFM is 50.75 units
Step-by-step explanation:
<u><em>The correct picture of the question in the attached figure</em></u>
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor
we have
△HFM∼△PST ----> given problem
step 1
Find the scale factor
Let
z ----> the scale factor

substitute the given values

step 2
Find the perimeter of triangle PST
Remember that the perimeter of a triangle is the sum of its three length sides

step 3
Find the perimeter of triangle HFM
we know that
If two figures are similar, then the ratio of its perimeters is equal to the scale factor
so
The perimeter of triangle HFM is equal to the perimeter of triangle PST multiplied by the scale factor
so

Answer:
c = -4
Step-by-step explanation:
If f(x) = 2x^3 - x + c and f(2) = 10, plug in 2 for the x values in the function and make the function output 10.
10 = 2(2^3) - 2 + c Now, we only have to deal with one variable, that is c.
10 = 2(8) - 2 + c
10 = 16 - 2 + c
10 = 14 + c
-4 = c After simplifying, we get that c is -4.
To check this, plug in 2 for x, and -4 for c in the function. If the function produces 10 as the result, the halleluja!
f(2) = 2(2^3) - 2 - 4
f(2) = 2(8) - 2 - 4
f(2) = 16 - 2 - 4
f(2) = 10