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RoseWind [281]
2 years ago
11

Difference between compounded annually, monthly and daily.

Mathematics
1 answer:
zvonat [6]2 years ago
5 0

Answer:

With monthly compounding, the bank will calculate interest on your account just once per month. It will not update your balance on a daily basis when it calculates how much interest it owes you. Assuming that the APR is the same, accounts with monthly compounding offer a lower APY than accounts with daily compounding.

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Teachers in a medium-sized suburban school district have an average salary of $47,500 per year, with a standard deviation of $4,
natima [27]

Answer: $49,875; $4,830C.

Step-by-step explanation:

The average salary of Teachers in a medium-sized suburban school district is $47,500 per year.

The standard deviation is $4,600

After negotiating with the school district, teachers recieve a 5% raise and a one-time $500 bonus. The bonus of $500 will not alter the mean and standard deviation because equal amount is added for each teacher.

5% increase in each teacher's salary would differ. Therefore, it will affect the mean and standard deviation by 5%. Therefore, the new mean would be

47500 + (5/100 × 47500) = $49875

The new standard deviation would be

4600 + (5/100 × 4600) = $4830

7 0
3 years ago
Read 2 more answers
Dr. Smith gives his staff a `1/3` bonus if they exceed the quarterly goal. This quarter, they exceeded the goal by $1,500. What
vovangra [49]
You have to multiply:
1/3 * 1500 = 500.
6 0
3 years ago
If cos(θ)= -2/3 and θ lies in quadrant II, find the value of cotθ
Lera25 [3.4K]

\text{Given that,}\\\\\cos \theta = - \dfrac 23\\\\\implies \cos^2 \theta  = \dfrac 49\\\\\implies 1- \sin^2 \theta = \dfrac 49\\\\\implies \sin^2 \theta =1-\dfrac 49\\\\\implies \sin^2 \theta =\dfrac 59\\\\\\\text{Now,}\\\\\cot^2 \theta = \dfrac{\cos^2 \theta}{\sin^2 \theta} \\\\\\\implies \cot^2 \theta = \dfrac{\tfrac 49}{\tfrac 59}\\\\\\\implies \cot^2 \theta = \dfrac 49 \times \dfrac 95\\\\\\\implies \cot^2 \theta = \dfrac 45\\\\\\

\implies \cot \theta = \pm\sqrt{\dfrac 45} =  \pm \dfrac 2{\sqrt 5}\\\\\\\text{Since}~ \theta ~ \text{lies in the second quadrant,}  \cot \theta ~\text{will be negative.}\\\\\text{Hence,}~ \cot \theta = - \dfrac{2}{\sqrt 5}

6 0
2 years ago
Read 2 more answers
Select the correct answer.
Elena L [17]

Answer:

b because first u need to remove the parentheses then u disturbe

8 0
3 years ago
In two or more complete sentences, explain how to solve the cube root equation, ^3√x+1 -2=0
IrinaVladis [17]

Explanation:

The first step is to figure out what the equation is. When unconventional math symbols are used, and when there are no grouping symbols identifying operands, that can be the most difficult step. Here, we think the equation is supposed to be ...

  \sqrt[3]{x+1}-2=0

It usually works well in radical equations to isolate the radical. Here that would mean adding 2 to both sides of the equation, to undo the subtraction of 2.

  \sqrt[3]{x+1}=2

Now, it is convenient to raise both sides of the equation to the 3rd power.

  x+1=2^3=8

Finally, we can isolate the variable by undoing the addition of 1. We accomplish that by adding -1 to both sides of the equation.

  x=7

The equation is solved. The solution is x = 7.

5 0
3 years ago
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