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Diano4ka-milaya [45]
2 years ago
15

Which of the following values are in the range of the function graphed below?

Mathematics
1 answer:
zubka84 [21]2 years ago
5 0

The values in the range of the function graphed below are; Option D. 1 and Option E. 1/2

<h3>What is domain and range of a function?</h3>

The domain is the set of values for which the given function is defined.

The range is the set of all values which the given function can output.

we know that

The domain is the interval ----> [-1,1]

-1 ≤ x ≤ 1

The domain is all real numbers greater than or equal to -1 and less than or equal to 1

The range is the interval ----> [0,1]

0 ≤ y ≤ 1

The range is all real numbers greater than or equal to 0 and less than or equal to 1

Hence, The values that are in the range are 1 and 1/2

Learn more about appropriate domain here:

brainly.com/question/20073127

#SPJ1

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Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo
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Answer:

a

  P(a | e') =  0.22

  P(b | e') =  0.28

  P(c | e') =  0.33

b

  P(a | e' , d' , b') = 0.57

Step-by-step explanation:

From the question we are told that

   The probabilities are

Supplier  chosen            A                     B                    C            

Probability                P(a) = 0.20       P(b) =  0.25   P(c) =  0.15      

                                       D                      E

                                P(d) =  0.30     P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(a | e') =  \frac{P (a \  and \  e')}{P(e')}

      P(a | e') =  \frac{P (a)}{P(e')}

     P(a | e') =  \frac{P (a)}{1- P(e)}

=>   P(a | e') =  \frac{ 0.20}{1- 0.10}

=>   P(a | e') =  0.22

Generally the new probability of companies B  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(b | e') =  \frac{P (b \  and \  e')}{P(e')}

      P(b | e') =  \frac{P (b)}{P(e')}

     P(b | e') =  \frac{P (b)}{1- P(e)}

=>   P(b | e') =  \frac{ 0.25}{1- 0.10}

=>   P(b | e') =  0.28

Generally the new probability of companies C  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(c | e') =  \frac{P (c \  and \  e')}{P(e')}

      P(c | e') =  \frac{P (c)}{P(e')}

     P(c | e') =  \frac{P (c)}{1- P(e)}

=>   P(c | e') =  \frac{ 0.15}{1- 0.10}

=>   P(c | e') =  0.17

Generally the new probability of companies D  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(d | e') =  \frac{P (d \  and \  e')}{P(e')}

      P(d | e') =  \frac{P (d)}{P(e')}

     P(d | e') =  \frac{P (d)}{1- P(e)}

=>   P(d | e') =  \frac{ 0.30}{1- 0.10}

=>   P(c | e') =  0.33

Generally the probability that  B, D , E  are not chosen this year is mathematically represented as

      P(N) =  1 - [P(e) +P(b) + P(d) ]

=>       P(N) =  1 - [0.10 +0.25  +0.30 ]

=>       P(N) =  0.35

Generally the probability that A is chosen given that E , D , B  are rejected this year is mathematically represented  as

      P(a | e' , d' , b') =  \frac{P(a)}{P(N)}

=>     P(a | e' , d' , b') =  \frac{0.20 }{0.35 }    

=>     P(a | e' , d' , b') = 0.57

5 0
3 years ago
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