we are given with a circle with the center at (3,3) and one that passes through (6,5). The equation of a circle is (x-h)^2 + (y-k)^2 = r^2. In this case h = 3 and k = 3. Substituting, h and k and x = 6 and y = 5, r^2 is obtained to be 13. Among these points, A. point (1,6) fits to the equation.
Answer: cos A=4/5
Step-by-step explanation:
soh, cah, toa
Adjacent A is 32, hypotenuse is 40
32/40 simplifies to 4/5
Answer:
(7,4)
Step-by-step explanation:
The midpoint formula is:

Let (5,6) be x₁ and y₁ and let's let (9,2) be x₂ and y₂. Thus, the midpoint is:

Add:

Divide by 2:

So, our midpoint is (7,4).
And we're done!
Answer:
210 yd²
Step-by-step explanation:
If we rotate the shape we get a right angle triangle with a hypotenuse of 29 yd :
The area of a right angle triangle is given by the formula :
A =
Substituting the 2 values given in diagram gives us :
A =
= 420÷2 = 210
Our units will be yd² as we are dealing with area
3 is the leading coefficient of the x term