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kondaur [170]
2 years ago
14

Determine the period of each function

Mathematics
1 answer:
Arisa [49]2 years ago
5 0

Answer: hmmm, all i could say it is 2,2 function, you have to calculete the other parts yourself.

Step-by-step explanation:

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The table below shows the amount Amelia earned babysitting. Find the rate of change
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1 : 8

Step-by-step explanation:

6 0
3 years ago
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If P(event A) = 0.25, what is P(not event A)?
xz_007 [3.2K]

Answer:

0.75

Step-by-step explanation:

The probability of P(not event a) is equal to 1-p(event A)

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3 years ago
I need help. Because is an important homework.​
Stella [2.4K]

i write everything in the exploration

Step-by-step explanation:

MN=31

KN=45

K=61°

L=119°

M=61°

CF=10

FE=15

CE=14

GD=11

QR=19

SR=24

PT=21

SQ=20

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7x-2=12x-22

-2=5x-22

20=5x

x=4

7×4-2=26 (12×4-22=26)

(2x+11)×2=8x-14

4x+22=8x-14

22=4x-14

36=4x

x=9

( (2×9+11)×2=58. 8×9-14=58. so it's correct)

(3x+5)+(9x-17)=180

12x-12=180

12x=192

x=16

( (3×16+5)+(9×16-17)=53+127=180 so it's correct)

10x-27=2x+29

8x-27=29

8x=56

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10×7-27=43 (2×7+29=43)

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5 0
3 years ago
g Suppose a factory production line uses 3 machines, A, B, and C for making bolts. The total output from the line is distributed
Vladimir [108]

Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

P(D) = P(A\cap D) + P(B\cap D) + P(C\cap D)

Recall that given events E,F the conditional probability of E given F is defined as

P(E|F) = \frac{P(E\cap F)}{P(F)}, from where we deduce that

P(E\cap F) = P(E|F)P(F).

We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345

We are told to calculate P(A|D), then using the formulas we have

P(A|D) = \frac{P(A\cap D)}{P(D)}= \frac{P(D|A)P(A)}{P(D)}= \frac{0.05\cdot 0.25}{0.0345}= 0.36231884

3 0
3 years ago
A 1000 KG car has 50,000 joules of kinetic energy. What is the speed?
zhannawk [14.2K]
KE=1/2mv^2
50000=(0.5)(1000)v^2
v^2=50000/500
v^2=100
v=10 ms^-1
7 0
4 years ago
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