I believe that the answer is <span>17332.9 although i may be wrong. i divided 4,00 by 3 to find the number i should multiply 13 by to find the amount of rodents equivalent to the amount of snakes. i got 1333.33 repeating. i then multiplied 13 by 1333.33 and this is what i got. 17332.9</span>
The answer is A
1 5/6 *12= 22
Answer = 36.0 mph
As per the question,
Actual speed of the car = 40 mph.
Speedometer has a percent error of 10%.
The error can be negative as well as positive.
If the error is negative, it means speedometer is showing less speed than actual speed= - 10%
10 % of 40 = 4
speed shown by speedometer = 40 - (10% of 40) = 36 mph
If the error is positive, it means speedometer is showing more speed than actual speed = +10%
speed shown by speedometer = 40 + ( 10% of 40) = 44 mph
as per the given options, correct option is 36.0 mph
Answer:
I.
A is a 4 x 5 matrix => A: U -> V, dim U = 5, dim V = 4
Null space is exactly two dimensional plane
dim null (A) = 2
II.
Rank A = dim U - dim Null A = 5 - 2 = 3
III.
Number of linearly Independent columns of A is the rank of A = 3
IV.
Yes, The system Ax = b has no solution sometimes as range of A \neq V
V.
Yes,Sometimes Ax = b has a unique solution
VI.
Yes, sometimes Ax = b has infinitely many solutions
<span>(a) 2.09302406
(b) Lower limit of 95% confidence interval = 185.85
(a) To get the t-score, first determine the number of degrees of freedom you have. That's simply the number of samples minus 1, so in this case we have 19 degrees of freedom. Then calculate (1-0.95)/2 = 0.05/2 = 0.025 which is the size of the tail for the confidence interval you want. Finally, lookup in a T-Distribution Table for the 19 degrees of freedom and tail size. The value looked up will be 2.09302406.
(b) Once you have the t-score, to calculate your desired interval, calculate the following:
V = T*SD/sqrt(n)
where
V = Variance
T = T-score
SD = Standard deviation
n = number of samples
So let's plug in the values and calculate V
V = T*SD/sqrt(n)
V = 2.09302406*21.02/sqrt(20)
V = 2.09302406*21.02/4.472135955
V = 43.99536574/4.472135955
V = 9.837662849
Your 95% confidence interval is now the mean +/- V. So
lower limit = 195.69 - 9.84 = 185.85
upper limit = 195.69 + 9.84 = 205.53</span>
