Answer:
measure angle OML = 26°
Explanation:
Let's consider the two triangles OML and OMN, we have:
measure angle MOL = measure angle MON
ON = OL
OM is a common sides
Therefore, based on SAS (side-angle-side):
ΔOML is congruent to ΔOMN
From this congruency, we have:
measure angle L = measure angle N
9x - 8 = 7x + 8
9x - 7x = 8 + 8
2x = 16
x = 8
Therefore:
measure angle L = 9(8) - 8 = 64°
measure angle N = 7(8) + 8 = 64°
Now, in triangle OML, we have:
angle NOM is an exterior angle of the triangle. This means that its measure is equal to the summation of the other two non-adjacent angles.
This means that:
measure angle NOM = measure angle L + measure angle OML
90 = 64 + measure angle OML
measure angle OML = 90 - 64 = 26°
Hope this helps :)
$67.34. if you multiply the total amount of money he has (259) by the percentage of (74) you will get (19,166). you then will divide the total by (100). which then gives you ($191.66) that will be given off. so you then subtract the total of money he has (259) by (191.66) which will give you (67.34). he will be paying ($67.34).
Answer:
0.5 = 50% probability a value selected at random from this distribution is greater than 23
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability a value selected at random from this distribution is greater than 23?
This is 1 subtracted by the pvalue of Z when X = 23. So
has a pvalue of 0.5
0.5 = 50% probability a value selected at random from this distribution is greater than 23
9514 1404 393
Answer:
True; about 120° CCW rotation about Q
Step-by-step explanation:
Triangle A'B'C' appears to be congruent to triangle ABC and about the same distance from point Q. The angle of rotation from ABC to A'B'C' appears to be about 120° counterclockwise when measured using a geometry program.
Triangle A'B'C' is the image of triangle ABC under rotation about 120° CCW about point Q.
_____
<em>Additional comment</em>
If choices of rotation angle are ±135° or ±165°, the best choice would be ...
135°
http://www.purplemath.com/modules/specfact.htm
