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Len [333]
3 years ago
15

A rectangular pyramid is sliced so the cross section is perpendicular to its base but does not pass through its vertex.

Mathematics
2 answers:
likoan [24]3 years ago
8 0

The answer is a trapazoid

julsineya [31]3 years ago
6 0

Answer:

if it's a rectangular pyramid a rectangle

Step-by-step explanation:

the cross sectional area is the shape at the bottom

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wariber [46]
The answer for each large square represents 1 whole is number4
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3 years ago
Landry's neighbor pledged $5.00 for every 2 miles he swims in a charity swim-a-thon. If Landry swims 3 miles how much money will
SVETLANKA909090 [29]
7.50 dollars because per each mile its $2.50 . and $2.50 times 3 equals $7.50
7 0
4 years ago
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Given the equation 2x = 4y - 3 write another linear equation that would create a system that has the number of solutions listed
Harman [31]

Answer:

A. 2x-4y=\pi
B.  x=1

C. 2x-4y=3

Step-by-step explanation:

A. 2x-4y=\pi. Any number could work as long as the coefficients for x and y stays the same. You are basically imposing that the quantity 2x-4y (if you bring 4y to the LHS) is equal to both -3 AND \pi, or any number you like. But yesterday was 3/14 so let's pick a fun number!

B.  x=1 Or y=1. Or as long as you don't pick the same ratios of x and y you're golden. But x=1 is the easiest that comes to mind

C. 2x-4y=3. To get infinitely many solutions you just have to rewrite the equation again. Maybe move things around if you prefer, or multiply everything by a number you lile.

7 0
2 years ago
What is the value of 9a + 6b?​
Svetlanka [38]

i) 3a+2b=9     /*3

9a+6b=27

ii) 8x+6y=60   /: 2

4x+3y=30

6 0
4 years ago
Read 2 more answers
A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .
Eduardwww [97]

Answer:  \bold{S_{\infty}=\dfrac{3125}{2}=1562.5}

<u>Step-by-step explanation:</u>

  a₁,  375,  a₃,   a₄,  81

First, let's find the ratio (r). There are three multiple from 375 to 81.

375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}

Next, let's find a₁

a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}

7 0
3 years ago
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