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Leviafan [203]
2 years ago
11

The length of a rectangle is four times the width. The perimeter of the rectangle is 45 inches. Write a system of equations that

represents this problem. What is the area of the rectangle​
Mathematics
1 answer:
Nady [450]2 years ago
8 0

Step-by-step explanation:

2×length + 2×width = 45

length = 4×width

now, we are using the second equation (a variable identity) in the first equation

2×4×width + 2×width = 45

8×width + 2×width = 45

10×width = 45

width = 45/10 = 4.5 in

length = 4×width = 4×4.5 = 18 in

the area of the rectangle is

length × width = 18 × 4.5 = 81 in²

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Answer:

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Step-by-step explanation:

So we have the fraction:

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We can do this algebraically. Follow to following steps:

Let's let this number equal to n. Thus:

0.31111...=n

Since there is only 1 digit repeating, let's multiply everything by 10. So:

3.1111...=10n

Now, subtract n from both sides:

3.1111-n=10n-n

On the left, substitute the number for n. On the right, combine like terms:

3.1111...-0.31111...=9n

All of the 1s will cancel. So:

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Subtract:

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Divide both sides by 9:

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And we're done!

Use a calculator to check:

14/45\stackrel{\checkmark}{=}0.31111...

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