Answer:
i just took the test its (4,1)
Step-by-step explanation:
The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
Read more about binomial expansion at
brainly.com/question/13602562
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Step-by-step explanation:
-8 - -4= -8+4=-4
16- -4=20
8- -4=12
-9--4=-5
Answer:
(f · g)(x) = 4x³ + x² - 20x - 5
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Combining Like Terms
- Expand by FOIL (First Outside Inside Last)
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 4x + 1
g(x) = x² - 5
(f · g)(x) is f(x)g(x)
<u>Step 2: Find (f · g)(x)</u>
- Substitute: (f · g)(x) = (4x + 1)(x² - 5)
- Expand [FOIL]: (f · g)(x) = 4x³ - 20x + x² - 5
- Combine like terms: (f · g)(x) = 4x³ + x² - 20x - 5