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Ira Lisetskai [31]
3 years ago
6

The ratio of quarters to dimes in a coin collection is 5:3. You add the same number of new quarters as dimes

Mathematics
1 answer:
Anon25 [30]3 years ago
3 0

The ratio of quarters to dimes is not still 5 : 3

<u>Solution:</u>

Given that ratio of quarters to dimes in a coin collection is 5:3 .

You add same number of new quarters as dimes to the collection .  

Need to check if ratio of quarters to dimes is still 5 : 3

As ratio of dimes and quarters is 5 : 3

lets assume initially number of quarters = 5x and number of dimes = 3x.

Now add same number of new quarters as dimes to the collection

Let add "x" number of quarters and "x" number of dimes

So After adding,

Number of quarters = initially number of quarters + added number of quarters = 5x + x = 6x

Number of dimes = initially number of dimes + added number of dimes

= 3x + x = 4x

New ratio of quarters to dimes is 6x : 4x = 3 : 2

So we have seen here ratio get change when same number of new quarters and dimes is added to the collection

Ratio get change from 5 : 3 when same number of new quarters and dimes is added to the collection and new ratio will depend on number of quarters and dimes added to collection.

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Answer:

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Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

The probability in favor of the regulation based on the recent survey is:

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Let X the random variable of interest "Number of favor respondents about the regulation", on this case we now that:

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And we want to find this probability:

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If we use X= "Number of respondednts opposed to the regulation we got the same answer", but on this case p = 1-0.68=0.32, and we want this probability:

P(X=4)=(6C4)(0.32)^4 (1-0.32)^{6-4}=0.0727

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