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Paha777 [63]
1 year ago
10

Solve the following to become to brainliest

Mathematics
1 answer:
Lelechka [254]1 year ago
3 0

Answer:

  0

Step-by-step explanation:

To find the slope between the two given points, you can use the given formula for the slope between two points.

__

<h3>given</h3>

The points are (x1, y1) = (-3, 2) and (x2, y2) = (4, 2).

The formula is ...

  slope = (y2 -y1)/(x2 -x1)

__

<h3>use the formula</h3>

Substituting the given values into the formula gives ...

  slope = (2 -2)/(4 -(-3)) = 0/7 = 0

The slope of the line is zero.

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Answer:

answer choice D I hope this helped

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Louisa savings change - $9 each time she goes bowling. In all, it changed by -99 during the summer. How many times did she go bo
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Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
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Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

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