Invested amount (P) = $300.
Time in years (t) = 2 years.
Balance after 2 years (A) = $329.49.
Let us assume rate of interest = r % compounds annually.
We know, formula for compound interest

Plugging values in formula, we get




Taking square root on both sides, we get





r=0.048.
Converting it into percentage by multiplying by 100.
r=0.048 × 100
r = 4.8 %
Therefore, the rate of interest on the account is 4.8% compounds annually.
Your answer is C
It's hard to describe I did it all in my head but please trust me that C is correct