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BaLLatris [955]
2 years ago
5

Cosmo’s family has a pool like this.

Mathematics
1 answer:
Verdich [7]2 years ago
7 0

a. The volume of the pool is 27.483 m³

b.  The number of litres of water the pool will hold is 27483 L

c. The pool will fill at a rate of 50 L/min in 549.7 min

The pool is a cylinder, so, we need to find its volume

<h3>a. What is volume of the pool?</h3>

Since the pool is a cylinder, its volume is, V = πd²h/4 where

  • d = width of pool = 5.4 m and
  • h = height of pool = 120 cm = 1.20 m

So, V = πd²h/4

= π(5.4 m)² × 1.20 m/4

= π × 29.16 m² × 1.20 m/4

= 34.992π m³/4

= 8.748π m³

= 27.483 m³

So, the volume of the pool is 27.483 m³

<h3>b. How many litres of water will the pool hold?</h3>

Since the volume of the pool, V = 27.483 m³ and 1000 Litres = 1 m³

So, the volume of the pool in litres is V = 27.483 m³

= 27.483 × 1 m³

= 27.483 × 1 000 L

= 27483 L

So, the number of litres of water the pool will hold is 27483 L

<h3>c. How long will it take to fill the pool at a rate of 50 L/min?</h3>

Since the volume of the pool is V = 27483 L, the time it will take the pool to fill at a rate of 50 L/min is given by t = Volume/rate

= 27483 L/50 L/min

= 549.66 min

≅ 549.7 min

So, how long will it take to fill the pool at a rate of 50 L/min is 549.7 min

Learn more about volume of pool here:

brainly.com/question/11893973

#SPJ1

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Element X decays radioactively with a half life of 12 minutes. If there are 160
Salsk061 [2.6K]

Answer:

It would take 75.8 minutes for the element to decay to 2 grams.

Step-by-step explanation:

The number of grams of element x, after t minutes, is given by the following equation:

X(t) = X(0)(1-r)^{t}

In which X(0) is the initial amount and r is the decay rate.

There are 160 grams of Element X

This means that X(0) = 160.

So

X(t) = X(0)(1-r)^{t}

X(t) = 160(1-r)^{t}

Half life of 12 minutes.

This means that X(12) = 0.5*X(0) = 0.5*160 = 80. So

X(t) = 160(1-r)^{t}

80 = 160(1-r)^{12}

(1 - r)^{12} = 0.5

\sqrt[12]{(1 - r)^{12}} = \sqrt[12]{0.5}

1 - r = 0.9438

So

X(t) = 160(1-r)^{t}

X(t) = 160(0.9438)^{t}

How long would it take for the element to decay to 2 grams?

This is t for which X(t) = 2. So

X(t) = 160(0.9438)^{t}

2 = 160(0.9438)^{t}

(0.9438)^{t} = \frac{2}{160}

\log{(0.9438)^{t}} = \log{\frac{2}{160}}

t\log{0.9438} = \log{\frac{2}{160}}

t = \frac{\log{\frac{2}{160}}}{\log{0.9438}}

t = 75.8

It would take 75.8 minutes for the element to decay to 2 grams.

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A Coffee table was $129.99 and on sale for 20% off. The sales tax is 8.5%. How much do we save?
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Answer:

Step-by-step explanation:

Discount = 20% of 129.99

=\frac{20}{100}*129.99\\\\=25.998

= $26

Price after discount = 129.99 - 26 = $103.99

Tax = 8.5% of 103.99

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Selling price including tax = 103.99 + 8.84

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Amount saved = 129.99 - 112.83

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