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1 year ago

Determine if x-3 is a factor of f(x)=x^3-x^2-5x-3

Mathematics

2 answers:

soldier1979 [14.2K]1 year ago

7 0

Answer:

(x - 3) is a factor of the given function

Step-by-step explanation:

Given function:

$\implies f\:\!\:(x)=x^3-x^2-5x-3$

If (x - 3) is a factor of the given function then $f\:\!\:(3) = 0$

Substitute x = 3 into the function and solve:

$\implies f\:\!\:(3)=(3)^3-(3)^2-5(3)-3$

$\implies f\:\!\:(3)=27-9-15-3$

$\implies f\:\!\:(3)=0$

Therefore, as $f\:\!\:(3) = 0$ then (x - 3) is a factor of the given function.

lord [1]1 year ago

5 0

Step-by-step explanation:

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mylen [45]

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<u><em>Solution:</em></u>

Given that Tracie ran a total of $5\frac{3}{4}$ miles on Saturday and Sunday

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From given question,

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$\rightarrow \frac{23}{4} -\frac{13}{8}\\\\\rightarrow \frac{23 \times 2}{4 \times 2}-\frac{13}{8}\\\\\rightarrow \frac{46}{8} - \frac{13}{8}\\\\\rightarrow \frac{46-13}{8} = \frac{33}{8}$

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Thus Tracie ran $\frac{33}{8}$ miles or $4\frac{1}{8}$ miles on sunday

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