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1 year ago

H14

Mathematics

1 answer:

lys-0071 [83]1 year ago

4 0

uh I don't unerstand that :(

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What is the slope of the line shown below?

Sophie [7]

Hi there!

$\large\boxed{slope = \frac{1}{5}}$

Use slope formula to solve for the slope of the line:

$slope = \frac{y_{2}-y_{1} }{x_{2} -x_{1} }$

Plug in points into the equation. We can use the points (0, -10) and (25, -5):

$slope = \frac{-5-(-10) }{25 -0 } = \frac{5}{25} = \frac{1}{5}$

3 0

3 years ago

1.4x10 -2 in standard form

sesenic [268]

Answer:

Step-by-step explanation:

1.4x10 is moving the decimal point one spot to the left, so it would be 14., which is just simply 14. Finally, 14-2=12 which is the answer.

4 0

2 years ago

Find the value of x if g(x) = - 18 for g(x) = 2x - 8

nalin [4]

Hi there!

$\large\boxed{x = -5}$

Find the value of 8 by substituting in -18 for g(x):

-18 = 2x - 8

Add 8 to both sides:

-10 = 2x

Divide both sides by 2:

-10/2 = 2x/2

x = -5

8 0

2 years ago

Read 2 more answers

How can csc^2-cot^2 = 1?

Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

$\csc^{2} (x) - \cot^{2} (x) = 1$

Take the left hand side and simplify to get the right hand side.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1}{\sin^{2} (x)} - \frac{ \cos^{2} (x)}{\sin^{2} (x)}$

Collect LCM for the denominators.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1 - \cos^{2} (x)}{\sin^{2} (x)}$

Recall the Pythagorean Identity.

$\cos^{2} (x) + \sin^{2} (x) = 1$

This implies that:

$1 - \cos^{2} (x) = \sin^{2} (x)$

We substitute this to get,

$\csc^{2} (x) - \cot^{2} (x) = \frac{\sin^{2} (x)}{\sin^{2} (x)}$

$\csc^{2} (x) - \cot^{2} (x) = 1$

6 0

2 years ago

Please help me with this question I also need to see the steps if possible!

umka21 [38]

Hi there!

To solve, we must use the following trig identity:

sin(u - v) = sin(u)cos(v) - sin(v)cos(u)

We can rewrite the left hand side of the equation as:

$\frac{sin(u)cos(v)-sin(v)cos(u)}{sin(u)cos(v)}$

Split the fraction:

$\frac{sin(u)cos(v)}{sin(u)cos(v)} - \frac{sin(v)cos(u)}{sin(u)cos(v)} =$

First fraction reduces to 1:

$1 - \frac{sin(v)cos(u)}{sin(u)cos(v)} =$

Simpify each with common arguments:

$1 - tan(v)cot(u)$

4 0

2 years ago