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dmitriy555 [2]
2 years ago
14

H14

Mathematics
1 answer:
lys-0071 [83]2 years ago
4 0

uh I don't unerstand that :(

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Solve the equation x^2+17x+12=-3x^2 to the nearest tenth.
mote1985 [20]

Answer:

x=-\frac{17}{8}+\frac{\sqrt{97} }{8} or x=-\frac{17}{8}-\frac{\sqrt{97} }{8}

Step-by-step explanation:

x^2+17x+12=-3x^2

Add 3x^2 on both sides.

x^2+17x+12+3x^2=-3x^2+3x^2

x^2+17x+12+3x^2=0

Combine like terms;

4x^2+17x+12=0

Use the quadratic formula;

a=4

b=17

c=12

x=\frac{-b\frac{+}{}\sqrt{b^2-4ac}  }{2a}

x=\frac{-(17)\frac{+}{}\sqrt{(17)^2-4(4)(12)}  }{2(4)}

x=\frac{-17\frac{+}{}\sqrt{289-192}  }{8}

x=\frac{-17\frac{+}{}\sqrt{97}  }{8}

x=-\frac{17}{8}+\frac{\sqrt{97} }{8} or x=-\frac{17}{8}-\frac{\sqrt{97} }{8}

6 0
3 years ago
1/16^3x=64^2(x+8)<br> Solve for x.
SSSSS [86.1K]

Answer:

x = -4

Step-by-step explanation:

16 = 4*4 = 4²

64 = 4 * 4* 4 = 4³

(\dfrac{1}{16})^{3x}=64^{2*(x+8)}\\\\\\(16^{-1})^{3x}=64^{2x + 16}\\\\\\16^{-3x}=64^{2x +16}\\\\(4^{2})^{-3x}=(4^{3})^{2x+16}\\\\4^{-6x}=4^{6x +48}

As bases are same, compare exponents

6x + 48 = -6x  

Subtract 48 from both sides

6x = -6x - 48

Add '6x' to both sides

6x + 6x = -48

12x = -48

Divide both sides by 12

x = -48/12

x = -4

3 0
2 years ago
Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k. k = ______ Graph of two lines. f of x equa
Nat2105 [25]

Solution:

As given , g(x)= f(x) + k --------(1)

As also given : f(x) = \frac{1}{3}(x+2)

g(x) =  \frac{1}{3}(x+5)

Putting the value of f(x) and g(x) in equation (1).

→ \frac{1}{3}(x+5) = \frac{1}{3}(x+2) + k

→ \frac{1}{3}[x+5-x-2]= k

→ k = \frac{1}{3} \times 3=1

So , the value of k is 1.

7 0
4 years ago
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