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1 year ago

Solve algebraically for all x values

Mathematics

2 answers:

den301095 [7]1 year ago

6 0

X= 5
Simplify the equation

x=4=36-12x + X^2
Move the expression to the left
x-4-36+12x-x^2=0
Collect like terms
Calculate
13x-40-x^2=0
Reorder the terms

-x^2+13x-40 = 0
Change the signs
-x^2+13x+40=0
Rewrite the expression
x^2-5x-8×+40=0
Factor the expressions
x•( x-5)-8(x-5 )=0
Factor the expression
(x-5)•(x-8)=0
Separate into possible cases
x-5=0
x-8=0
Solve the equations
x=5
x=8
Check the solutions
6=6
10=6
x=5 is a solution
x=8 is not a solution

Delicious77 [7]1 year ago

4 0

<h2><u>Radical Equations</u></h2>

<h3>Solve algebraically for all x values</h3>

√(x - 4) + x = 6

To solve for x, make sure to remove first the radical sign before simplifying. To remove the radical sign (since it is square root) raise each side of the equation with an exponent of 2.

√(x - 4)² + x = 6
x - 4 + x = 6

Then start simplifying.

x - 4 + x = 6
x + x - 4 = 6
2x = 10
x = 5

<u>Answer:</u>

The value of x is <u>5</u>.

Wxndy~~

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