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raketka [301]
2 years ago
10

Solve log x = 2. 100 1,000 2 20

Mathematics
1 answer:
dybincka [34]2 years ago
5 0

keeping in mind that when the logarithm base is omitted, the base 10 is assumed.

\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x

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Six friends share 8 fruit bars equally. How many fruit bars does each friend get?
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0.75 friends per fruit

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If testing the claim that sigma subscript 1 superscript 2 baseline not equals sigma subscript 2 superscript 2σ21≠σ22​, what do w
12345 [234]

Answer:

The statistic for this system of hypothesis is given by:

F=\frac{s^2_1}{s^2_2}

If the statistic is equal to 1 then that means s^2_1 = s^2_2 and we don't have enough evidence to conclude that the two population variances and deviations are different.

Step-by-step explanation:

System of hypothesis

We want to test if the variation for a group1 is equal to another one 2, so the system of hypothesis are:

H0: \sigma^2_1 = \sigma^2_2

H1: \sigma^2_1 \neq \sigma^2_2

Calculate the statistic

The statistic for this system of hypothesis is given by:

F=\frac{s^2_1}{s^2_2}

If the statistic is equal to 1 then that means s^2_1 = s^2_2 and we don't have enough evidence to conclude that the two population variances and deviations are different.

6 0
3 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
Which graph correctly matches the equation y = 2-x?
nalin [4]

Answer:  The answer is attached in the figure.


Step-by-step explanation:  Given are four different graphs and we are to check which one matches with the equation y = 2 - x.

We have the following points on this equation.

(0,2), (1,1), (2,0), etc.

When we try to match these points with the given graphs, the we see that these points does not match with the first, third and fourth graph. The only graph containing these points is second one.

Thus, the second option is correct. Also see the attached figure for the location of the three mentioned points.


4 0
3 years ago
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