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2 years ago

Solve log x = 2. 100 1,000 2 20

Mathematics

1 answer:

dybincka [34]2 years ago

5 0

keeping in mind that when the logarithm base is omitted, the base 10 is assumed.

$\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x$

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<h3>Question:-</h3>

To find the Binomial theorem form of $\bold{(4t-3)^{5}}$

As in Binomial theorem :-

${(x - y)}^{5} = {x}^{5} - 5 {x}^{4} y + 10 {x}^{3} {y}^{2} - 10 {x}^{2} {y}^{3} + 5x {y}^{4} - {y}^{5}$

<h3>Solution :-</h3>

$= {(4t - 3)}^{5}$

Hence, on using the Binomial theorem,

$= {(4t)}^{5} - 5 {(4t)}^{4} (3)+ 10 {(4t)}^{3} {(3)}^{2} - 10 {(4t)}^{2} {(3)}^{3} + 5(4t) {(3)}^{4} - {(3)}^{5}$

On formatting

$= {1024t}^{5} - 5 ({256t}^{4} )(3)+ 10 ({64t}^{3} ) (9 ) - 10 ({16t}^{2} )(27) + 5(4t) (81) - 243$

On further formatting.

$= {1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$

Hence, the required answer is :-

${1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$

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