Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
<span>4.045 x10^-3 in standard notation = 4,045</span>
Answer:
15cm
Step-by-step explanation:
All you need to do for this is divide the perimeter (60) by the number of sides on a square (4). 60÷4=15
Number 2 is 1.00 and Number 3 is 1.50
Answer:
2^2 * 2^3 = 32
2^5 = 32
Step-by-step explanation:
2*2*2*2*2 = 32