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Gre4nikov [31]
2 years ago
12

X=4-2yx+3y=12 What value of x satisfies the system of equations?

Mathematics
1 answer:
IRINA_888 [86]2 years ago
7 0

Answer: x= -12

Step-by-step explanation: 1. I assumed that the system was actually two equations: x = 4-2y and x + 3y = 12.

2. From there I took the value of x in the first equation and placed it into the second equation to get 4 - 2y + 3y = 12

3. This gets us to 4 + y = 12 and thus y = 8.

4. Put that value back into the first equation and you have x = 4 - 2(8) = 4 - 16 = -12.

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Four square pieces of corkboard are lined up to make a rectangle. The area of the entire corkboard is
Pavel [41]

9514 1404 393

Answer:

  a) attached

  b) 100 square inches, 1/4 of the total

  c) square root of area

  d) multiply by 4

Step-by-step explanation:

a) A diagram is attached

__

b) If the total area consists of 4 squares of the same size, then the area of one square will be 1/4 of the total area. 1/4 of 400 square inches is 100 square inches, the area of one square.

__

c) The area of a square is the square of the side length. You find the side length by finding the square root of the area. √(100 in²) = 10 in, the side length of each square.

__

d) The rectangle is 4 squares laid side by side, so its length is 4 times the side length of one square: 4×10 in = 40 in.

4 0
3 years ago
SOMEBODY PLEASE HELP!!!!<br> GIVING 98 POINTS
marusya05 [52]
What is the question if it 98-49 than it would be 49
5 0
3 years ago
Read 2 more answers
What is the value of x?
IgorLugansk [536]

Answer:

x is equal to give

Hope am correct

7 0
3 years ago
Read 2 more answers
Please answer asap!!!!!
kherson [118]

Step-by-step explanation:

The equation of a circle can be the expanded form of

\large \text{$(x-a)^2+(y-b)^2=r^2$}(x−a)

2

+(y−b)

2

=r

2

where rr is the radius of the circle, (a,\ b)(a, b) is the center of the circle, and (x,\ y)(x, y) is a point on the circle.

Here, the equation of the circle is,

\begin{gathered}\begin{aligned}&x^2+y^2+10x-4y-20&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4-49&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &x^2+10x+25+y^2-4y+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &(x+5)^2+(y-2)^2&=&\ \ 7^2\end{aligned}\end{gathered}

⟹

⟹

⟹

⟹

x

2

+y

2

+10x−4y−20

x

2

+y

2

+10x−4y+25+4−49

x

2

+y

2

+10x−4y+25+4

x

2

+10x+25+y

2

−4y+4

(x+5)

2

+(y−2)

2

=

=

=

=

=

0

0

49

49

7

2

From this, we get two things:

\begin{gathered}\begin{aligned}1.&\ \ \textsf{Center of the circle is $(-5,\ 2)$.}\\ \\ 2.&\ \ \textsf{Radius of the circle is $\bold{7}$ units. }\end{aligned}\end{gathered}

1.

2.

Center of the circle is (−5, 2).

Radius of the circle is 7 units.

Hence the radius is 7 units.

4 0
3 years ago
How many ways can you distribute $4$ identical balls among $4$ identical boxes?
Harman [31]

Answer:

5 ways

Step-by-step explanation:

We have to name the cases.

1. 4 - 0 - 0 - 0

2. 3 - 1 - 0 - 0

3. 2 - 2 - 0 - 0

4. 2 - 1 - 1 - 0

5. 1 - 1 - 1 - 1

We don't name 0 - 0 - 1 - 3 or 0 - 1 - 1 - 2 etc. because it is the same thing.

4 0
3 years ago
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