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Advocard [28]
3 years ago
5

Sove equation for x. 3/8x =4/3​

Mathematics
2 answers:
Zina [86]3 years ago
8 0
Here you go (:


HOW I SOLVED:

Veronika [31]3 years ago
7 0
32/9
Or
3 5/9 how I got my answer was simple
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Answer:

-6

Step-by-step explanation:

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I'll GIVE YOU BRAINLIEST ANSWER!!! If someone can help me with this problem???
frez [133]
The answer is 3x^2 - 3x - 3 with a remainder of -3
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For your vegetable garden, you plan to plant 5 12 of it in corn, 1 6 in different kinds of beans, and 1 12 in tomatoes. You will
Ymorist [56]

Answer:

\frac{2}{9}  part of the garden will be planted in onions and squash combined.

Step-by-step explanation:

Given:

For your vegetable garden, you plan to plant 5 12 of it in corn, 1 6 in different kinds of beans, and 1 12 in tomatoes.

You will plant the remainder equally in eggplant, onions, and squash.

Now, to find the part of garden that will be planted in onions and squash combined.

Part of garden plan for planting corn = \frac{5}{12}

Part of garden plan for planting kinds of bean = \frac{1}{6}

Part of garden plan for planting tomatoes = \frac{1}{12}

So, adding all the parts of corn, beans and tomatoes:

\frac{5}{12}+\frac{1}{6}  +\frac{1}{12} \\\\=\frac{5+2+1}{12} \\\\=\frac{8}{12}

Now, to get the rest of the parts of garden use to plant eggplant, onions, and squash we subtract \frac{8}{12} from 1 whole:

1-\frac{8}{12} \\\\=\frac{12-8}{12} \\\\=\frac{4}{12}

As, given planting the remainder equally in eggplant, onions, and squash.

So, each will be planted in part of:

\frac{4}{12} \div 3

=\frac{4}{12}\times \frac{1}{3}

=\frac{4}{36}

On simplifying it:

=\frac{1}{9}.

Thus, \frac{1}{9}  part of the garden for each eggplant, onions, and squash.

Now, to get the part of the garden will be planted in onions and squash combined we add \frac{1}{9} part of garden planting for onions and \frac{1}{9} of squash:

\frac{1}{9} +\frac{1}{9} \\\\=\frac{1+1}{9} \\\\=\frac{2}{9}

Therefore, \frac{2}{9}  part of the garden will be planted in onions and squash combined.

6 0
4 years ago
Read 2 more answers
GUYS PLEASE ANSWER! I'M DESPERATE! WILL MARK BRAINLIEST
uysha [10]
A. Graph B because the slope is at a constant rate
B. Graph A because since it is slowly opened the rise of the slope starts of small then rises more
C. Graph C since it’s opened a lot the beginning and closed at the end so the rise would start high then go lower as time goes by
8 0
4 years ago
Read 2 more answers
QUESTION 1: What are the values of cos α and tan α, if α is an acute angle in a right triangle: sin α = 40/41 -------- cos α = ?
zhuklara [117]

Answer:

Question 1:

cos a = 0.2195

tan a = 4.445

Question 2:

sin a = 0.8

tan a = 1.333

Step-by-step explanation:

<h3 /><h3>Question 1:</h3>

Given that;

sin a = 40/41

a = sin ⁻¹ (40/41)

a = 77.32°

Now we have to find the value of cos a and tan a:

a = 77.32°

cos 77.32° = 0.2195

tan 77.32° = 4.445

<h3>Question 2:</h3>

Given that;

cos a = 0.6

a = cos ⁻¹ (0.6)

a = 53.13°

Now we have to find the value of cos a and tan a:

a = 53.13°

sin 53.13° = 0.8

tan 53.13° = 1.333

4 0
3 years ago
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