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Snowcat [4.5K]
2 years ago
7

A hyperbola centered at the origin has a vertex at (0,−40) and a focus at (0, 41). which are the equations of the asymptotes? y

= ±x y = ±x y = ±x y = ±x
Mathematics
1 answer:
lord [1]2 years ago
7 0

The equations of the asymptotes of the given hyperbola are; y = ±(40/9)x

<h3>How to Interpret the equation of a hyperbola?</h3>

We are given;

Vertex at (0,−40)

Focus at (0, 41).

Thus, the equation of the asymptote of the given hyperbola is;

y = ±(40/(√41 - (-40))

y = ±(40/(√81)

y = ±40/9

Read more about Hyperbola Equation at; brainly.com/question/13003184

#SPJ1

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