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VARVARA [1.3K]
3 years ago
5

It takes Sarah 50 minutes to walk to her friends house 1 3/4 miles away. What is her walking pace in miles per hour?

Mathematics
1 answer:
Yuki888 [10]3 years ago
7 0

0.035 mph is how fast she is walking

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Write a for loop that computes the following sum: 5 10 15 20 ... 485 490 495 500. The sum should be placed in a variable sum tha
Varvara68 [4.7K]

The solution is in the attachment

8 0
3 years ago
A new carpet cleaning company claims that they can clean 3 times as many carpets in 1 week as another company. If both companies
inna [77]

Answer:

The number of carpets cleaned by new company per week  is 249

Step-by-step explanation:

Let us assume :

The number of carpets cleaned by old company in 1 week = m

So, the number of carpets cleaned by new company in 1 week

= 3 x ( Number of carpets cleaned by old company)

 = 3 (m) = 3 m

Total carpet cleaned altogether in a week  = 332

So, Total Carpets cleaned by both companies in 1 week

= Number of carpets cleaned by ( Old + New) company in 1 week.

=  m + 3  m =  4 m

⇒  4  m = 332

or, m = 332 / 4 = 83  , or m = 83

Hence number of carpets cleaned by old company per week = m = 83

The number of carpets cleaned by new company per week

= 3 m =  3 x 83= 249

8 0
3 years ago
Solve the equation. 2(y – 4) = 4 SHOW YOUR WORK!
ahrayia [7]

2(y−4)=4

(2)(y)+(2)(−4)=4

2y+−8=4

2y−8=4

2y−8+8=4+8

2y=12

\frac{2y}{2}=\frac{12}{2}

y=6 is correct answer.

Hope this helps!

Thanks!

8 0
2 years ago
Cain has 40 eggs. He divides all the eggs and places an equal number into 10 small containers. How many eggs are in each contain
Tema [17]

Answer:

4

Step-by-step explanation:

40 ÷ 10 = 4

7 0
3 years ago
Read 2 more answers
A short-wave radio antenna is supported by two guy wires, 150 ft and 180 ft long. Each wire is attached to the top of the antenn
Dafna1 [17]

The distance between the anchor points of the two guy wires holding radio antenna is 181 feet (to the nearest foot)

<h3>How to determine the distance between the two anchor points of the guy wire</h3>

The problem will be solved using SOH CAH TOA

let the distance between the 150 ft long guy wire and the radio antenna be x

let the distance between the 180 ft long guy wire and the radio antenna be y

cos 65° = x / 150

x = cos 65° * 150

x = 63.39 ft

The height of the antenna

sin 65° = height of antenna / 150

height of antenna = sin 65 * 150

height of antenna = 135.95

using Pythagoras theorem

(length of guy wire)² = (height of the antenna)² + (anchor distance)²

(anchor distance)² = 180² - 135.95²

anchor distance = √(180² - 135.95²)

anchor distance = 117.97

The anchor points distance apart

= 63.39 + 117.97

= 181 (to the nearest foot)

Learn more on Pythagoras theorem here:

brainly.com/question/29241066

#SPJ1

4 0
1 year ago
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