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olga55 [171]
1 year ago
10

If 0 lies in the quadrant IV. What can be the value of cos 0 ?​

Mathematics
2 answers:
meriva1 year ago
8 0

Answer:

Between 0 and 1

Step-by-step explanation:

Cos Θ is the x coordinate of the unit circle. The points of that circle in quadrant IV have an x coordinate of 0≤x≤1.

Flura [38]1 year ago
5 0

Answer:

the value of cos 0 is 7

Step-by-step explanation:

because you have to times it twice

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Diego is solving the equation x^2-12x = 21
uysha [10]

Answer:

The solutions to the quadratic equations will be:

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Step-by-step explanation:

Given the expression

x^2-12x\:=\:21

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x^2-12x\:=\:21

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x^2-12x+\left(-6\right)^2=\left(x-6\right)^2

so the expression becomes

\left(x-6\right)^2=57

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-6=\sqrt{57}

add 6 to both sides

x-6+6=\sqrt{57}+6

Simplify

x=\sqrt{57}+6

also solving

x-6=-\sqrt{57}

add 6 to both sides

x-6+6=-\sqrt{57}+6

Simplify

x=-\sqrt{57}+6

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Answer:

Option 4 is correct

Step-by-step explanation:

If the rate is compounded continuously, the formula used to find the future value is:

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