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valkas [14]
3 years ago
10

A survey of 500 farmers showed that of the​ farmers, 121 grew only​ wheat, 108 grew only​ corn, 92 grew only​ oats, 195 grew​ wh

eat, 59 grew wheat and​ corn, 48 grew wheat and​ oats, and 176 grew corn. Determine the number of farmers who ​a) grew at least one of the​ three, ​b) grew all​ three, ​c) did not grow any of the​ three, and ​d) grew exactly two of the three.
Mathematics
1 answer:
kondaur [170]3 years ago
5 0

Answer:

The farmers in regions II, IV, and VI had exactly two of the three Summing the numbers in these regions 25 + 15 + 10 we find the that 50 farmers grew exactly two of the three.

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Point A is the midpoint of side XZ and point B is the
Katyanochek1 [597]

Answer:

Option (2)

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Point A is the midpoint of side XZ and point B is the  midpoint of side YZ.

Triangle XYZ is cut by line segment AB. Point A is the midpoint of side XZ and point B is the midpoint of side YZ. The length of XY is (5x - 7), the length of AB is (x + 1), and the lengths of XA and ZA are (2x - 2). The lengths of YB and BZ are congruent.

What is AX ?

2 units

4 units

6 units

8 units

From the figure attached,

XYZ is a triangle having A and B as the midpoints of the sides XZ and YZ.

By the theorem of midpoints,

AB = \frac{1}{2}\text{(XY)}

Since AB = (x + 1) and XY = (5x - 7)

(x + 1) = \frac{1}{2}(5x-7)

2x + 2 = 5x - 7

5x - 2x = 2 + 7

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Therefore, side AB = 3 + 1 = 4 units

Side XY = (5x - 7)

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