Question

Integrate this y=2x In(x²) at point x=3​

Answer 1

Answer:

Step-by-step explanation:

y=∫ln(x^2) (2x) dx

=ln (x^2) (x^2)-∫(2x/x^2) (x^2) dx+c

=x² ln (x²)-∫2x dx+c

=x²ln(x²)-x²+c

=x²[ln(x²)-1]+c

integration is between an interval so don't understand at x=3