What are the x-coordinates of the solutions to this system of equations?

What is 6 more than 7 times a number is 41

son4ous [18]

the problem would be set up as 6+(7*x)=41

first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41

7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9

so x =5.9

8 0

3 years ago

Eli has 7 games on his phone. His sister has 6 more than him. Which ratio compares the number of games on Eli’s phone to the num

sergij07 [2.7K]

Answer:

1 to 1.89 or 1:1.89

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which is the best estimate 9.6-6.2

velikii [3]

The best estimate is probably 4

6 0

3 years ago

Read 2 more answers

Find the missing side lengths. Leave your answers in simplest radical form.

saveliy_v [14]

ANSWER:
d. x = 15, y= 15√3

EXPLANATION:
This is a special triangle, more specifically a 30-60-90 degree triangle. For sake of not confusing x and y, we will use z to use as our reference for solving this triangle. The side lengths for each angle are as follows:
• 60 degrees = z√3
- this is the value for your y answer
• 30 degrees = z
- this is the value for your x answer
• Hypotenuse = 2z
- this is what we already have

We solve for what we already have which is the Hypotenuse = 30:
2x = 30
x = 15

We now have our x value which is 15.
Now we just plug in that x value for every expression for every angle.

x = 15
y = 15√3

Sorry if I explained it too thoroughly but I’ll be glad to answer any questions or clarifications

8 0

3 years ago

Please Help!!<br><br>Use Euler’s formula to write in exponential form.

LekaFEV [45]

Answer:

C, $4e^{i(7\pi/4)}$

Step-by-step explanation:

To remind you, Euler's formula gives a link between trigonometric and exponential functions in a very profound way:

$e^{ix}=\cos{x}+i\sin{x}$

Given the complex number $2\sqrt{2}-2i\sqrt{2}$ , we want to try to get it in the same form as the right side of Euler's formula. As things are, though, we're unable to, and the reason for that has to do with the fact that both the sine and cosine functions are bound between the values 1 and -1, and 2√2 and -2√2 both lie outside that range.

One thing we could try would be to factor out a 2 to reduce both of those terms, giving us the expression $2(\sqrt{2}-i\sqrt{2})$

Still no good. √2 and -√2 are still greater than 1 and less than -1 respectively, so we'll have to reduce them a little more. With some clever thinking, you could factor out another 2, giving us the expression $4\left(\frac{\sqrt{2}}{2} -i\frac{\sqrt{2}}{2}\right)$ , and <em>now </em>we have something to work with.

Looking back at Euler's formula $e^{ix}=\cos{x}+i\sin{x}$ , we can map our expression inside the parentheses to the one on the right side of the formula, giving us $\cos{x}=\frac{\sqrt2}{2}$ and $\sin{x}=-\frac{\sqrt2}{2}$ , or equivalently:

$\cos^{-1}{\frac{\sqrt2}{2} }=\sin^{-1}-\frac{\sqrt2}{2} =x$

At this point, we can look at the unit circle (attached) to see the angle satisfying these two values for sine and cosine is 7π/4, so $x=\frac{7\pi}{4}$ , and we can finally replace our expression in parentheses with its exponential equivalent:

$4\left(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}\right)=4e^{i(7\pi/4)}$

Which is c on the multiple choice section.

4 0

4 years ago