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2 years ago

Can anyone help me solve this?

Mathematics

1 answer:

Novay_Z [31]2 years ago

7 0

Answer:9

Step-by-step explanation:

Use the pythagorean theorem. $a^{2}+b^{2}=c^{2}$

We know both a and c, so it becomes

$4^{2}+b^{2}=\sqrt{97}^{2}$ =

16+b^2=97=

97-16=b^2=

81=b^2=

9=b

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What is the Genotypic and Phenotypic ratio?

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Answer:

The phenotypic ratios are the ratios of visible characteristics. The genotypic ratios are the ratios of gene combinations in the offspring, and these are not always distinguishable in the phenotypes.

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3 years ago

During the 7 minutes previous to landing, an airplane decreased in elevation by −3,192 feet. Determine the mean elevation change

GarryVolchara [31]

Answer:

The answer is -456 feet per minute.

Step-by-step explanation:

They are asking for the average elevation change per minute. Since there are 7 minutes, you would divide -3,192 by 7, and that would result in -456

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3 years ago

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Qual é a area de um campo de futebol ,sabendo que o seu cumprimento mede 24m e a sua largura mede 15 m

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Responder:

Área do campo de futebol = 360m²

Explicação passo a passo:

Dado que :

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Largura = 15 m

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3 years ago

PLEASE HELP QUICK Suppose a particle is moving along the x-axis. The position, measured in feet, of the particle can be modeled

Romashka-Z-Leto [24]

When 'x' is zero, 'y' is -9.

That simply means that when time began ... when the starter

fired his pistol and the clock started running ... the particle

was 9 units 'before' zero, in the region of negative location.

By the way ... the way the question is written is enough to confuse

anyone, and I hope that hasn't contributed to your trouble with it.

If the particle is moving along the x-axis, then 'x' is its location,

and the time in seconds is something else. Say 't' for example.

Also, if it's moving along the x-axis, then 'y' is always zero.

The position of the particle is modeled by an equation like

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4 years ago

Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual

Stells [14]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

$A\cap B\subset A$ and $A\cap B\subset B$

$P(A\cap B)\leq P(A)$ and $P(A\cap B)\leq P(B)$

$P(A\cap B)\leq 0.6$ and $P(A\cap B)\leq 0.4$

From these two inequalities we conclude that

$P(A\cap B)\leq 0.4$

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let $P(A\cap B)=0.3$

We need to find the probability that student has one of these two types of cards.

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Substitute the given values.

$P(A\cup B)=0.6+0.4-0.3=0.7$

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

$P(A'\cup B')=1-P(A\cup B)$

$P(A'\cup B')=1-0.7=0.3$

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

$A-B$

It can also written as

$A\cap B'$

The probability of this event is

$P(A\cap B')=P(A)-P(A\cap B)$

$P(A\cap B')=0.6-0.3=0.3$

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

$P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)$

$P(A\cap B')+P(A\cap B')=0.7-0.3$

$P(A\cap B')+P(A\cap B')=0.4$

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

8 0

3 years ago