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Oduvanchick [21]
4 years ago
6

Miguel is making an obstacle course for field day. At the end of every sixth of the course, there is a tire. At the end of every

third of the course, there is a cone. At the end of every half of the course, there is a hurdle. At which locations of the course will people need to go through more than one obstacle?

Mathematics
1 answer:
Mkey [24]4 years ago
8 0
Hey there, 

I think this might help u

Hope this helps u!!

~ TRUE BOSS

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HELP PLEASE!! IM REALLY STUPID!! // You have nickels and dimes in your wallet with a total value of $1.10. You have 17 coins in
Dmitry [639]

Answer:

x=12 (12 nickels))

y=5 (5 dimes)

Step-by-step explanation:

Based on the information given in the problem, you can set up the following system of linear equations, where:

x: number of nickels.

y: number of dimes.

Then

FIRST EQUATION: x+y=17

SECOND EQUATION: 5x+10y=110  (in cents)

You can apply the Substitution method:

- Solve for x from the first equation.

- Substitute into the second equation and solve for y.

 Then:

x=17-y

5(17-y)+10y=110\\85-5y+10y=110\\5y=25\\y=5

- Find x:

x=17-5\\x=12

5 0
3 years ago
Since opening night, attendance at play A has increased steadily, while attendance at play B first rose and then fell. Equations
lina2011 [118]
The two lines intersect at the point (4, 214). This means that the attendance was 214 for both plays on the 4th night. 

<span>B. The attendance was the same on day 4. The attendance was 214 at both plays that day.</span>
3 0
3 years ago
Read 2 more answers
PLEASE HELP… <br> !!!!!!!
valentina_108 [34]

Answer:

LM=11

Step-by-step explanation:

LN= ML+MN

4x+9=(2x+7)+(3x)

4x+9=5x+7

5x-4x= 9-7

x=2

LM=2x+7 =2(2)+7=4+7=11

5 0
3 years ago
Read 2 more answers
At the beginning of the day, you have a 30-oz bottle of medication. if each dose is 1/2 oz, how many doses in total do you have?
Feliz [49]
Your answer would be 60 ounces.
7 0
3 years ago
What is the 87th term of the arithmetic sequence of 12,0,-12
den301095 [7]

Step-by-step explanation:

12,0,-12

a1 = 12 \\ a2 = 0 \\ d = a2 - a1 \\ d = 0 - 12 =  - 12 \\ an = a1 + (n - 1) \times d \\  \\ a87 = 12 + (87 - 1) \times ( - 12)  \\ a87 = 12  - 1032

7 0
3 years ago
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