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kari74 [83]
2 years ago
15

What is the factored form of 4x2 23x – 72? (4x 8)(x – 9) (4x – 8)(x 9) (4x 9)(x – 8) (4x – 9)(x 8)

Mathematics
1 answer:
klasskru [66]2 years ago
7 0

Answer:

(x+8)(4x-9)

Step-by-step explanation:

Rewrite expression 4x^2 + 32x - 9x - 72

Factor out 4x  4x(x+8) - 9x - 72

Factor out x+8  4x(x+8) - 9(x+8)

Simplify (x+8)(4x-9)

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Answer:

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3 years ago
Find the value of x and the value of y.
jeka57 [31]

Answer:

x =  6/√3  ,   y = 12/√3

Step-by-step explanation:

sin 60° = opposite /hypothenus

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cross multiply

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tan 60° = √3

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4 years ago
Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students
12345 [234]
<span>In general, the height of a projectile is given by

</span>h= -\frac 1 2 g t^2 + v t + h_0
<span>
where </span>h is the height at time t of a projectile shot upward at velocity v from initial height h_0<span>.

The acceleration of gravity </span>g= 9.8 \textrm {m/s}^2 \textrm{ or } g=32\textrm{ feet/s}^2.<span>  We give it a negative sign in the equation because it pulls down.

Let's apply it to each group.

Group A launches a tennis ball straight up with an initial velocity of 19 meters per second.

We have MKS units, positive (upward) velocity and an initial height of 0.

</span>h= -\frac 1 2(9.8) t^2 + (19) t + 0 = -4.9t^2 + 19t
<span>
Group B launches a tennis ball straight up with an initial velocity of 50 feet per second.    Not metric, velocity +50, initial height zero.

</span>h= -16t^2 + 50t
<span>
Group C drops a tennis ball from a height of 19 meters.

MKS, initial height 19, initial velocity zero.

</span>h= -\frac 1 2 g t^2 + v t + h_0 = -4.9 t^2 + 19
<span>
Group D drops a tennis ball from a height of 50 feet. 

</span>h= -16 t^2 + 50
<span>


</span>
6 0
4 years ago
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FromTheMoon [43]

Answer:

Step-by-step explanation:

Y-Y1= m(x-x1)

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Y-6=57x-114

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6 0
3 years ago
Divide. Reduce the answer to lowest terms.<br><br> 2 1/9 ÷ 3 1/3
nevsk [136]

Answer:

7/31 is the answer you are looking

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3 years ago
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