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Leviafan [203]
3 years ago
7

Point is plotted at 30.05 on a number line which describes the location point

Mathematics
1 answer:
spayn [35]3 years ago
5 0

Answer:

Step-by-step explanation:

A point is plotted at 30.05 on a number line. Which of the options describes the location point?

There are no options to choose from but below is the description of the location point:

30.05 units to the east of the center of the number line. The center of the number line is point zero (0) and separates the negative side from the positive side. 30.05 is on the positive side.

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Find p(-3) if p(x)= 4x^3 - 5x^2 + 7x - 10.
andriy [413]

Answer:

p(-3) = -184

Step-by-step explanation:

p(-3) = 4(-3)^3 - 5(-3)^2 + 7(-3) -10

        = 4(-27) - 5(9) - 21 - 10

        = -108 - 45 - 21 - 10

        = -184

replace x with -3 and then solve

       

7 0
3 years ago
Perform the indicated operation. 4/11 ÷ 4/9 9/11 16/99 1 2/9
Natalka [10]
Evaluate
Exact Form:
9/11

Decimal Form:
0.81∞

Answer: 9/11
Hope this helps! :)
6 0
3 years ago
Solve the equation x^5-4x^4+4x^3+2x^2-5x+2=0
sergejj [24]

Answer:

x = 2 or x = 1 or x = -1

Step-by-step explanation:

Solve for x over the real numbers:

x^5 - 4 x^4 + 4 x^3 + 2 x^2 - 5 x + 2 = 0

The left hand side factors into a product with three terms:

(x - 2) (x - 1)^3 (x + 1) = 0

Split into three equations:

x - 2 = 0 or (x - 1)^3 = 0 or x + 1 = 0

Add 2 to both sides:

x = 2 or (x - 1)^3 = 0 or x + 1 = 0

Take cube roots of both sides:

x = 2 or x - 1 = 0 or x + 1 = 0

Add 1 to both sides:

x = 2 or x = 1 or x + 1 = 0

Subtract 1 from both sides:

Answer:  x = 2 or x = 1 or x = -1

3 0
3 years ago
Please help me with 2b ASAP. <br> Really appreciate it!!
Bogdan [553]

f(x)=\dfrac{x^2}{x^2+k^2}

By definition of the derivative,

f'(x)=\displaystyle\lim_{h\to0}\frac{\frac{(x+h)^2}{(x+h)^2+k^2}-\frac{x^2}{x^2+k^2}}h

f'(x)=\displaystyle\lim_{h\to0}\frac{(x+h)^2(x^2+k^2)-x^2((x+h)^2+k^2)}{h(x^2+k^2)((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{(x+h)^2-x^2}{h((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2xh+h^2}{h((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2x+h}{(x+h)^2+k^2}

f'(x)=\dfrac{2xk^2}{(x^2+k^2)^2}

\dfrac{k^2}{(x^2+k^2)^2} is positive for all values of x and k. As pointed out, x\ge0, so f'(x)\ge0 for all x\ge0. This means the proportion of occupied binding sites is an increasing function of the concentration of oxygen, meaning the presence of more oxygen is consistent with greater availability of binding sites. (The question says as much in the second sentence.)

7 0
3 years ago
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10
MaRussiya [10]

Answer:

13

Step-by-step explanation:

because

5 0
3 years ago
Read 2 more answers
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