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2 years ago

Solve for x −5(-3x-3)+5x+4=-1

1 answer:

5 0

<h3> Simple and best practice solution for -5(-3x-3)+5x+4=-1 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.</h3>

<h3>Solve for x</h3><h3 /><h3>−5(-3x-3)+5x+4=-1</h3><h2>Solution for -5(-3x-3)+5x+4=-1 equation:</h2><h2 /><h2 /><h2>-5(-3x-3)+5x+4=-1</h2><h2 /><h2>We move all terms to the left:</h2><h2 /><h2>-5(-3x-3)+5x+4-(-1)=0</h2><h2 /><h2>We add all the numbers together, and all the variables</h2><h2 /><h2>5x-5(-3x-3)+5=0</h2><h2 /><h2>We multiply parentheses</h2><h2 /><h2>5x+15x+15+5=0</h2><h2 /><h2>We add all the numbers together, and all the variables</h2><h2 /><h2>20x+20=0</h2><h2 /><h2>We move all terms containing x to the left, all other terms to the right</h2><h2 /><h2>20x=-20</h2><h2 /><h2>x=-20/20</h2><h2 /><h2>x=-1</h2><h2 /><h2> </h2><h2> </h2><h2 /><h3>See similar equations:</h3><h3>| 2x+5=0.5(4x+10) | | x+(x-11)=43 | | 39-v=56 | | 3x-4x+8=-5x+4x-9 | | -3+8u=5(u- | | -4(-2x-2)+x-2=?48 | | 2x+10=+2x+10 | | 13=-3a-5 | | 7y=64-y | | w-5/7=72/3 | | 58y+7=34y?3 | | -36=4(v-5)-6v | | 3x-4-5x=x=4=x | | ?4(r+2)=4(2?2r) | | y/2=22 | | 6x+12-x=x+8 | | -3/8y=0 | | 7(2=-x)=3(x+2) | | x-x=234 | | 0=(2x-4)(x+6) | | -8x+-7=-15 | | 16x-x=100 | | 5k+21=17k=-3 | | 14x-x=37 | | 1-4x-8=8 | | w-33=12 | | (13x+20)=(7x+38) | | -3(2b+-5)=3b | | 30x-x=473 | | 13x-10=6x+4 | | y=-2,y=-16/8 | | (17.155)^2=(0)^2+2a(-15) |</h3>

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3 years ago

Read 2 more answers

If four tires can be changed in 3/4 of an hour gow long would it take to change 19 cars

kobusy [5.1K]

Answer:

14.25 hours

Step-by-step explanation:

Four tires = 3/4 of an hour

=> 1 car = 3/4 of an hour

=> 19 cars = ?

=> If 1 = 3/4

=> 19 = 3/4 x 19

=> 3/4 x 19

=> 57/4

=> 14.25 hours

So, it would take 14.25 hours for 19 car's tires to be changed.

5 0

3 years ago

Indicate whether the following analysis involves a statistical test. If it does involve a statistical test, state the population

Pie

Answer:

Yes it involves a statistical test

The population parameter(s) of interest is

The sample size is n = 100

The average reaction time of the right hands for the right-handed participants $\mu_R$

The average reaction time of the left hands for the left-handed participants $\mu_L$

The null hypothesis is $H_o : \mu_R = \mu_L$ ,

The alternative hypothesis is $H_a: \mu_R < \mu_L$

Yes it involves a statistical test

The population parameter(s) of interest is

The sample size is n = 100

The average reaction time of the right hands for the right-handed participants $\mu_R$

The average reaction time of the left hands for the left-handed participants $\mu_L$

The null hypothesis is $H_o : \mu_R = \mu_L$ ,

The alternative hypothesis is $H_a: \mu_R < \mu_L$

Yes it involves a statistical test

The population parameter(s) of interest is

The percentage of people in the community living in a mobile home is denoted with p

The sample size is n = 1000

The null hypothesis is $H_o : p =10\% = 0.01$ ,

The alternative hypothesis is $H_a: p >10\% = 0.01$

Step-by-step explanation:

Considering the first statement

Testing 100 right-handed participants on the reaction time of their left and right hands to determine if there is evidence for the claim that the right hand reacts faster than the left.

Yes, the analysis does involve a statistical test.

The null hypothesis is $H_o : \mu_R = \mu_L$ ,

The alternative hypothesis is $H_a: \mu_R < \mu_L$

Here $\mu_R$ is the average reaction time of the right hands for the right-handed participants

and $\mu_L$ is the average reaction time of the left hands for the left-handed participants

Considering third statement

Polling 1000 people in a large community to determine if there is evidence for the claim that the percentage of people in the community living in a mobile home is greater then 10%.

The percentage of people in the community living in a mobile home is denoted with p

The sample size is n = 1000

The null hypothesis is $H_o : p =10\% = 0.01$ ,

The alternative hypothesis is $H_a: p >10\% = 0.01$

3 0

3 years ago