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2 years ago

Which expressions are equivalent to the given expression. y^-8y^3x^0x^-2

Mathematics

1 answer:

vesna_86 [32]2 years ago

8 0

$y^{-8} y^3 x^0 x^{-2}$ is equivalent to $y ^{-5} x ^{-2}\\$ .

<h3>What is a simplification of an expression?</h3>

Usually, simplification involves proceeding with the pending operations in the expression.

Simplification usually involves making the expression simple and easy to use later.

Given;

$y^{-8} y^3 x^0 x^{-2}$

Simplify

$y^{-8} y^3 x^0 x^{-2}\\\\y ^{-8+3} x ^{0-2}\\ \\y ^{-5} x ^{-2}\\$

Hence, $y^{-8} y^3 x^0 x^{-2}$ is equivalent to $y ^{-5} x ^{-2}\\$ .

Learn more about an expression here:

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3 years ago

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irina1246 [14]

Answer:

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Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

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To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

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$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

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murzikaleks [220]

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3 years ago

Which expressions are equivalent to the given expression. y^-8y^3x^0x^-2​

Which expressions are equivalent to the given expression. y^-8y^3x^0x^-2