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Arada [10]
3 years ago
6

16.527 to the nearest tenths place

Mathematics
2 answers:
Butoxors [25]3 years ago
8 0
I'm pretty sure it's 16.5

brilliants [131]3 years ago
4 0
16.527 to the nearest tenths place is 16.5 because round to the hundredth you get 16.53 then round again, you get 16.5. Hope it helps.
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A rectangle has vertices at these coordinates. (1, 2) , (3, 2) , (1, −8) What are the coordinates of the fourth vertex of the re
Ilya [14]

Answer:

The coordinates of the fourth vertex of the rectangle is (3,-8).

Step-by-step explanation:

It is given that a rectangle has vertices at these coordinates. (1, 2) , (3, 2) , (1, −8).

Let the coordinates of the fourth vertex of the rectangle be (x,y).

The diagonals of rectangle intersect each other at their midpoint.

Plot these points on a coordinate plane. From the graph it is noticed that the end point of one diagonal are (3, 2) and (1, −8).

Midpoint=(\frac{3+1}{2},\frac{2-8}{2})=(2,-3)

The end point of second diagonal are (1, 2) and (x,y).

Midpoint=(\frac{1+x}{2},\frac{2+y}{2})

Since the diagonals of rectangle intersect each other at their midpoint, therefore

(\frac{1+x}{2},\frac{2+y}{2})=(2,-3)

On comparing both the sides,

\frac{1+x}{2}=2\Rightarrow 1+x=4\Rightarrow x=3

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Therefore the coordinates of the fourth vertex of the rectangle is (3,-8).

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