Yall please help!!!!!! THANK YOUUU SO MUCHHH!!! Kinda lostttt
1 answer:
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Answer:
0.9792
Step-by-step explanation:
Data provided in the question:
Average gross sales = $1,240
Standard deviation = $180
sample size = 40
Now,
standard deviation of sample average
=
=
= 28.46
Now,
z value for 1200 = = -1.4,
and,
p value for (z = -1.4) = 0.0808
therefore,
P(average < $1200) = 0.0808
Thus,
probability that the average over the next 40 weekdays will exceed $1,200
= 1 - 0.808
= 0.9792
A graphing calculator can help you visualize the function and its various behaviors.
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F. Oblique asymptote y = 0
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6. The horizontal and vertical asymptotes are y=1, x=4, and there is a "hole" at x=-2. The appropriate choice is ...
F. Oblique asymptote y = 0
8. The denominator has degree 2 more than the numerator, so the end behavior will tend toward 0 as x gets large. The appropriate choice is ...
J. As x → ±∞, f(x) → 0