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3 years ago

13

Chelsea completes 35 math problems in 7 min.

1 answer:

Andru [333]3 years ago

3 0

Answer = 5 problems per minute

Because you do the number of problems divided by the minutes eg 35/7 = 5

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If you answer all ill give brainliest.

Nonamiya [84]

Answer:

1. 1 < 8

2. 7 > -17

3. n-6 (N could be 7)

4. -4 x 3= -12

5. -5/5= -1 since the sign means greater than or equal to, that could be right.)

6. 3>Z (1) - 1

5 0

2 years ago

Ax+3=23 if a=0 plz help

VladimirAG [237]

Answer:

x = $\frac{23}{a}$

Step-by-step explanation:

Given equation is,

ax + 3 = 23

To solve this equation for the value of x isolate the variable 'x' on the one side of the equation.

Step 1,

Subtract 3 from both the sides of the equation.

ax + 3 - 3 = 23 - 3

ax = 20

Step 2,

Divide the equation by a,

$\frac{ax}{a}=\frac{23}{a}$

x = $\frac{23}{a}$

Therefore, x = $\frac{23}{a}$ will be the answer.

6 0

3 years ago

What is an end point of a ray

Slav-nsk [51]

Answer:

The end point of a ray is A

Step-by-step explanation:

Hope this Helps

5 0

2 years ago

Austin's office is 360 square feet. Calculate the area of his office in square yards.

Marta_Voda [28]

It would be 40 Because there are 9 square feet is equal to 1 square yard

4 0

2 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago