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2 years ago

Anyone who is appearing in cuet 2022. Help i have not studied anything yet 20 days left How to prepare in less time?

Mathematics

2 answers:

Vladimir [108]2 years ago

7 0

<h3>**How to prepare for exams in less time ?**</h3><h3 /><h3>==> Answer : </h3><h3 />

Give yourself enough time to study. Organize your study space.
 Use flow charts and diagrams. Practice on old exams. 
Explain your answers to others.
Organize study groups with friends. Take regular breaks.
 Snack on brain food.

xoxo

Zara♡

icang [17]2 years ago

3 0

Answer:

use brainly it really helps with studies faster

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Find the missing number: QUICKLY PLEASE

sp2606 [1]

Answer:

Step-by-step explanation:

4 0

3 years ago

Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect

Tasya [4]

$4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1$

defines an ellipse centered at $(0,0)$ with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the $x$ -axis. So if cross sections are taken perpendicular to the $x$ -axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at $x=x_0$ will have a base of length

$\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}$
$\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}$

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a $\sqrt2:1$ ratio with either of the remaining legs. So if the hypotenuse is $\dfrac43\sqrt{9-{x_0}^2}$ , then either leg will have length $\dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}$ .

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is $\dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}$ .

Finally, $x_0$ can be chosen from any value in $-3\le x_0\le3$ . We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

$\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)$

and so the volume would be

$\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx$
$=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}$
$=16$

6 0

3 years ago

It takes Jupiter 11.862 years to revolve around the sun. It takes Saturn 17.596 more years than Jupiter to revolve around the su

Olin [163]

Answer:

29.458 years

Step-by-step explanation:

Bro this is easy, it's literally addition, pay attention in class, but thank you for the points

4 0

3 years ago

Homeroom Data of Tickets Sold:

cricket20 [7]

1. the mean is 16

2. the mean is 22.5

the formula that can be used to calculate the mean is

= sum of terms/number of terms

for the first question the mean can be calculated as follows

sum of terms= 20+15+19+16+10

= 80

number of terms= 5

mean= 80/5

= 16

for the second question the mean can be calculated as follows

sum of terms= 19+23+11+30+27+27+22+26+16+24

= 225

number of terms= 10

mean= 225/10

= 22.5

Hence the mean for the first expression is 16 and the mean for the second expression is 22.5

Please see the link below for more information

brainly.com/question/26159926?referrer=searchResults

8 0

3 years ago

Its 7:30am. What time would it be in 16hours ?

Genrish500 [490]

Answer:

11:30pm

Step-by-step explanation:

6 0

3 years ago

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Anyone who is appearing in cuet 2022. Help i have not studied anything yet 20 days left How to prepare in less time? ​

Anyone who is appearing in cuet 2022. Help i have not studied anything yet 20 days left How to prepare in less time?