From what I can pick up from your problem statement, you want to know "<span>a similar charm has a diameter of 4 cm what is the circumference." Please, would you use proper punctuation in your writing, for greater clarity:
"A</span><span> similar charm has a diameter of 4 cm. What is the circumference?"
The formula for the circumference of a circle, when the diameter is known, is
C=</span>

d or C=pi*d
In this case, with diamter 4 cm, the circumference, C, is 4pi cm.
Answer:
it equals 11 haha !
Step-by-step explanation:
have a great day/night :)
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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Answer:
see below
Step-by-step explanation:
f(x)= -(x-2)^2 +4
This is the vertex form of the equation for a parabola
y= a ( x-h)^2 +k where (x,k) is the vertex of the parabola
a = -1 h= 2 k = 4
The vertex is ( 2,4)