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Elanso [62]
3 years ago
12

The mean of a sequence of n numbers is m. If we split the sequence into two sequences of lengths n1 and n2 and compute their mea

ns m1 and m2, which of the following is TRUE?
Mathematics
1 answer:
Furkat [3]3 years ago
8 0

The mean of a sequence of numbers is the average.

The true statement is: \mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

The given parameters are:

\mathbf{Mean = m}

\mathbf{Size = n}

The mean of a dataset is calculated as:

\mathbf{Mean = \frac{\sum x}{Size}}

So, we have:

\mathbf{m = \frac{\sum x}{n}}

Multiply both sides by m

\mathbf{\sum x = mn}

When the sequence is split into two, we have:

\mathbf{\sum x_1 = m_1\times n_1}

\mathbf{\sum x_2 = m_2\times n_2}

Where:

\mathbf{\sum x_ = \sum x_1 + \sum x_2}

So, we have:

\mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

Hence, the true statement is: \mathbf{mn = m_1 \times n_1 + m_2 \times n_2}

Read more about mean and averages at:

brainly.com/question/16217700

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Step-by-step explanation:

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Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.

<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>

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Solving gives:

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