Because there's an even number of values in this set, there is two middle values rather than one (31 and 34). To find the median we need to add them together and divide the sum by 2 (31 + 34 = 65, 65/2= 32.5) Our final answer is 32.5.
An integer may be a multiple of 3.
An integer may be 1 greater than a multiple of 3.
An integer may be 2 greater than a multiple of 3.
It is redundant to say an integer is 3 greater than a multiple of 3 (that's just a multiple of 3, we've got it covered). Same for 4, 5, 6, 7...
Let's consider a number which is a multiple of 3. Clearly, we can write 3+3+3+3+... until we reach the number. It can be written as only 3's.
Let's consider a number which is 2 greater than a multiple of 3. If we subtract 5 from that number, it'll be a multiple of 3. That means we can write the number as 5+3+3+3+3+... Of course, the number must be at least 8.
Let's consider a number which is 1 greater than a multiple of 3. If we subtract 5 from that number, it'll be 2 greater than a multiple of 3. If we subtract another 5, it'll be a multiple of 3. That means we can write the number as 5+5+3+3+3+3+... Of course, the number must be at least 13.
That's it. We considered all the numbers. We forgot 9, 10, 11, and 12, but these are easy peasy.
Beautiful question.
Answer:
QR ≈ 16.2 ft
Step-by-step explanation:
Using the tangent ratio in the right triangle.
tan62° = 
= 
= 
( multiply both sides by 8.6 )
8.6 × tan62° = QR , then
QR ≈ 16.2 ft ( to the nearest tenth )
I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:
In Mathematica, you can check this result via
D[4/2*Pi*r^3, r]
Answer:
1
-0.7
Step-by-step explanation:
Both and -0.7 are negative so therefore, 1 is the greatest
is -0.6 which is greater than -0.7 so it's the 2nd greatest
and -0.7 is the least
