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vodomira [7]
2 years ago
13

What value of expression when y=4 3y^2+y+8

Mathematics
2 answers:
denpristay [2]2 years ago
5 0
Answer is 60 hope it helped
Alika [10]2 years ago
4 0

Answer:

Not to sure, but I have two answers

Step-by-step explanation:

3y (squared 2) + 1 + 8 or

3y (squared 2) + 5 + 8

(sorry if you get it wrong, not so good at mathś)

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How do I find QS here?
docker41 [41]
Answer: 12.

To solve this problem, let's first solve for x. Thi is easiest done by figuring what QR is in terms of x using two equations, both from different lines.

In the first line:
QR = 15 - 4x.

In the third line:
QR = 13x - 1 - x = 12x - 1.

Now, we have to set these equations equal to each other. 
15 - 4x = 12x - 1
15 = 16x - 1
16x = 16
x = 1

Next, we take line three, 13x - 1, and substitute x as 1. The answer is 12.
3 0
3 years ago
An angle measures 18.6° less than the measure of its complementary angle. What is the measure of each angle?
weeeeeb [17]

Answer:

X = 35.7 Y=54.3

Step-by-step explanation:

Let the 2 angles be called X and Y were X is the smaller angle

we know that both angles are complementary therefore
X+Y=90

X = Y - 18.6 ( Given )

Y - 18.6 + Y = 90 ( substitution)

2Y = 90 + 18.6

Y = 108.6/2

Y=54.3

X= Y-18.6= 54.3-18.6 = 35.7

Check : X + Y = 35.7+54.3=90

6 0
2 years ago
I need the answer please.
Anestetic [448]

2 1/4 = 9/4

(9/4)(8/5) = (9/1)(2/5) = 18/5 = 3 3/5 cups

5 0
3 years ago
Identify the center and radius of the circle given by the equation (x+2)^2+(y-5)^2=16
Andreyy89

Answer:

Center=(0,2)   Radius=(4)

Step-by-step explanation:

give me 5 star and thank me plz

8 0
3 years ago
Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 5.08 and angle θA = 25.6 ∘ measured in the sense from the +x
alexgriva [62]

Answer:

(A⃗ ×B⃗ )⋅C⃗ = - 76.415

Step-by-step explanation:

First we need to calculate (A⃗ ×B⃗ ) :

(A⃗ ×B⃗ ) = A.B.sin (α).n

Where A is the magnitude of A⃗

Where B is the magnitude of B⃗

Where α is the angle between A⃗ and B⃗ = 63.9 - 25.6 = 38.3

Finally n is the vector orthogonal to A⃗ and B⃗

n magnitude is 1 and his direction is given by the right hand-rule

so n = ( 0 , 0 , 1 )

(A⃗ ×B⃗ ) = A.B.sin (α).n = 5.08 . 3.94 . sin (38.3) . (0 , 0 , 1 ) = (0,0,12.4)

C⃗ can be written as C.(0,0,-1) because of his +z - direction

C.(0,0,-1) = 6.16.(0,0,-1) = (0,0,-6.16)

(A⃗ ×B⃗ )⋅C⃗ = (0,0,12.4).(0,0,-6.16) = -76.41480787 = -76.415

8 0
3 years ago
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