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dedylja [7]
2 years ago
15

Equation:-

5 - 0 - 6 + 2" alt="x + 5 = 5 - 0 - 6 + 2" align="absmiddle" class="latex-formula">
Solve for x..
Thanks​
Mathematics
2 answers:
Sindrei [870]2 years ago
6 0
Answer = -4
To solve for x, you need to isolate x on one side of the = sign and combine like terms.
Subtract 5 from both sides

X + 5 = 5-0-6+2
-5. -5
_____________
X= -4
Alecsey [184]2 years ago
5 0

Answer:

\large { \boxed{\sf x = -4}

Explanation:

Original Expression:

\rightarrow  \sf x + 5  = 5 - 0 - 6 + 2

Subtract '5' from both sides:

\sf \rightarrow x+5-5=5-0-6+2-5

Simplify the following:

\sf \rightarrow x=-0-6+2

Add/Subtract integers:

\sf \rightarrow x=-4

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In a basketball game, Team A defeated Team B with a score of 97 to 63. Team A won by scoring a combination of two-point baskets,
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Answer:

14 free throw baskets , 25 two point baskets and 11 three point baskets

Step-by-step explanation:

Let n₁ represent the number of free-throw baskets, n₂ represent the number of two point baskets and n₃ represent the number of three point baskets.

Now, from the question, the number of two point baskets, n₂ is greater than the free throw baskets by 11. This is written as n₂ = n₁ + 11. Also, the number of three point baskets n₃ is three less than the number of free point baskets. This is written as n₃ = n₂ - 3. Since our total number of points equals 97, it follows that, sum of number of points multiplied by each point equals 97. So, ∑(number of points × each point) = 97. Thus,

n₁ + 2n₂ + 3n₃ = 97. Substituting n₂ and n₃ from above, we have n₁ +2(n₁ + 11) + 3(n₁ - 3) = 97.

Expanding the brackets, we have, n₁ + 2n₁ + 22 + 3n₁ - 9 = 97

collecting like terms, we have 6n₁ + 13 = 97

6n₁ = 97 - 13

6n₁ = 84

dividing through by n₁ we have, n₁ = 84/6 =14

so n₁ our free throw baskets equals 14. Substituting this into n₂ our number of two point baskets equals n₂ = n₁ + 11 = 14 + 11 = 25. Our number of three point baskets n₃ = n₁ - 3. So, n₃ = 14 -3 = 11.

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