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wariber [46]
2 years ago
6

Plssssssssssssssssss answer corectly

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
7 0

Answer:

1.equilateral

2.isosceles

3.isosceles

4.isosceles and right

5.scalene

6.scalene and right

7.isosceles and right

8.isosceles

9.equilateral

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Which is greater<br> 30% of 30 or 28% of 32 ?<br> You must show your working.
Alborosie

Answer:

30% of 30 = 9

28% of 32 = 8.96

Step-by-step explanation:

0.30 x 30 = 9

0.28 x 32 = 8.96

5 0
3 years ago
Read 2 more answers
If the relation is a function, list the domain and range. If the relation is not a function, choose "not a function". C = {(9, 1
Deffense [45]

Answer:

A: Domain: {9, 8, 7, -5} Range: {1, -3, 5, 3}

Step-by-step explanation:

C = {(9, 1) (8, -3) (7, 5) (-5, 3)}

The domain is the inputs

Domain: { -5,7,8,9}

The range is the output

Range{ -3,1,3,5}

This is a functions since there is no input that goes to multiple outputs

4 0
4 years ago
Find the missing number 2 ?/4 = 11/4 ?/10 =4/5
fgiga [73]

Answer:

Step-by-step explanation:

1)

?/10 =4/5

?/5×2 =4/5

4×2/5×2 =8/10  ... the number is : 8

2)

?/4 = 11/4....the number is : 11

4 0
3 years ago
Derive the equation of the parabola with a focus at (2, −1) and a directrix of y = −one half.
yKpoI14uk [10]
Basically, the parabola has to have all points that are equidistant from the focus and the directrix, the directrix being a horizontal line, and the focus being a point given. To derive an equation from this you need to use the distance formula which I'm guessing you already know because you're already in precalc.
The gist of it is that we have a random point on the parabola (x,y), and the point (x,y) will be equidistant from both the focus and the directrix. If we use the distance formula, you get something like this:
\sqrt{(y-(- \frac{1}{2} ))^2} = \sqrt{(x-2)^2+(y-(-1)^2}
The square root of y-(-1/2) coming from the directrix, and the righthand side of the equal sign being derived from the focus.
All you need to do is simplify now!
<span>(y+\frac{1}{2})^2 = (x-2)^2+(y+1)^2 \\\ y^2+y+ \frac{1}{4} = x^2-4x+4 + y^2+2y+1 \\\ -y-\frac{3}{4} = x^2-4x+4 \\\ -y-\frac{3}{4} = (x-2)^2 \\\ -y = (x-2)^2+\frac{3}{4} \\\ y = -(x-2)^2-\frac{3}{4}
</span>
Hope I helped! 
3 0
4 years ago
Read 2 more answers
To what place is 220.0 accurate?
natulia [17]
the answer of the question is tens
5 0
4 years ago
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