What this question simply asks about is you write the numbers it gave you in only one digit by 10 to the power of n. Where n represents the number of shifts of the decimal point.
And to get this number to be one digit, then you have to approximate.
To approximate; you should always consider that less than 5 counts zero and 5 or more counts+1.
Example:
5.3 is approximately 5
5.5 is approx. 6
5.9 is also approx. 6
and so on.
So the final answers are;
1) 4*10^13
2) 5*10^-11
Please note that 10^positive integer will cause the decimal point to move to the right which means a number greater than 1, usually, while 10^negative integer means number smaller than 1, usually.
Hope this helps.
Factorize x²+7x+12 ===> (x+3)(x+4)
Factorize x²-3x-28 ===> (x-7)(x+4)
4x + 12 can be written====> 4(x+3)
Then the question could be written as follows:
[(x+3)(x+4) / (x-7)(x+4) ] / 4(x+3) = [(x+3)(x+4) / (x-7)(x+4) ].[4(x+30]
After simplification you get 1 / 4(x-7)
Answer:
(a) ΔARS ≅ ΔAQT
Step-by-step explanation:
The theorem being used to show congruence is ASA. In one of the triangles, the angles are 1 and R, and the side between them is AR. The triangle containing those angles and that side is ΔARS.
In the other triangle, the angles are 3 and Q, and the side between them is AQ. The triangles containing those angles and that side is ΔAQT.
The desired congruence statement in Step 3 is ...
ΔARS ≅ ΔAQT
