Let's assume
people were in the original group of winners as x
A group of winning ticket holders share equally 90,000,000 lottery
Before the money is divided, three more winning ticket holders are declared
so, total number of winning tickes =x+3
each persons share is reduced to 5,000,000
so, total money =5,000,000*(x+3)
and this must be equal to total money
now, we can solve for x
and we get
Subtrac both sides by 3
so,
number of people were in the original group of winners is 15 ...........Answer
Answer:
Multiply the second equation by −2 to get −8x − 6y = −30.
Step-by-step explanation:
{2x + 6y = 12
{4x + 3y = 15
{2x + 6y = 12
{−8x − 6y = −30 >> New Equation
* Doing this will give you <em>additive</em><em> </em><em>inverses</em><em> </em>of −6y and 6y, which result in 0, so they are both ELIMINATED.
** [3, 1] is your solution.
I am joyous to assist you anytime.
Answer: y = -35x + 105
Step-by-step explanation:
The graph represents a function that is between hours and miles and to determine the equation which belong to this graph, we need to find the slope first by using two points from the graph which are (0, 105) and (3, 0).
The definition of slope is
m = (y2 - y1)/(x2 - x1)
= (0-105)/3-0
= -105/3
= -35
The slope is -35 and remember that the slope is the coefficient of the variable x. Therefore, the answer is:
y = -35x + 105
First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx
(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
Answer:
140/56= 2,5$ every hot dog
175/2,5=70 hot dogs
70-56=14 more hot dogs to earn 175$
Step-by-step explanation:
