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3 years ago

Pleaseeeee help

Mathematics

2 answers:

s2008m [1.1K]3 years ago

7 0

All I know is that question 1 is B and I think for question 3 is Sammy is correct.

laiz [17]3 years ago

3 0

Was this answer correct

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rewrite the standard form equation below into slope-intercept form. x-2y=3 A. y=x+3 By=-3/2x-1/2 C.y=3/2x-1/2 D.y=1/2x-3/2

quester [9]

Let us start converting!

$x-2y=3 \ \textgreater \ \mathrm{Subtract\:}x\mathrm{\:from\:both\:sides} \ \textgreater \ x-2y-x=3-x$

$-2y=3-x \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}-2 \ \textgreater \ \frac{-2y}{-2}=\frac{3}{-2}-\frac{x}{-2}$

$\frac{-2y}{-2} \ \textgreater \ \mathrm{Apply\:the\:fraction\:rule}:\ \frac{-a}{-b}=\frac{a}{b} \ \textgreater \ \frac{2y}{2}$

$\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \ y$

$\frac{3}{-2}-\frac{x}{-2} \ \textgreater \ \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{3-x}{-2}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}\ \textgreater \ -\frac{-x+3}{2} \ \textgreater \ y = -\frac{3-x}{2}$

$Therefore... y=\frac{1}{2}x-\frac{3}{2} (Note: m=\frac{1}{2},\:b=-\frac{3}{2})$

M is the slope and b is the y intercept.

Hope this helps!

8 0

3 years ago

Please, Help!

Veronika [31]

Answer:

adults = 40

children = 68

Step-by-step explanation:

Let the children=c

Let the adults = a

Equations

a + c = 108 (1)

3.75a + 1.5c = 252 (2)

Multiply (1) by 1.5

1.5a + 1.5c = 162 (3)

Subtract (3) from (2)

3.75a + 1.5c = 252

1.5 a + 1.5c = 162 Subtract

2.25a = 90 Divide by 2.25

a = 90/2.25

a = 40

Find the number of children

a + c = 108

40 + c = 108

c = 108 - 40

c = 68

Check

LHS

3.75 * 40 + 1.50 * 68

150 + 102

252 Which checks with the right hand side.

7 0

4 years ago

Can some please help me with number 19 and 20

stepladder [879]

Answer:

20. is 36 19. is 46/79

Step-by-step explanation:

49 divides by 36 and in high school is like this and yeah

7 0

3 years ago

Can someone please help me

Bezzdna [24]

I think C

number is correct

7 0

4 years ago

Let a and b be natural numbers with b>0.prove that we can write $a

vagabundo [1.1K]

I’m not sure what the answer is but I’m sure it’s gonna be great

3 0

4 years ago