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Reil [10]
2 years ago
9

Help will name brainliest

Mathematics
1 answer:
liberstina [14]2 years ago
5 0

\text{For angle N,}\\\\PQ= \text{Perpendicular.}\\\\QN = \text{Hypotenuse.}\\\\\text{Now,}\\\\\sin N = \dfrac{\text{Perpendicular}}{\text{Hypotenuse}}\\\\\\~~~~~~~=\dfrac{QP}{QN}

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